使用 Apache NiFi 进行复杂的转换和过滤

如何解决使用 Apache NiFi 进行复杂的转换和过滤

我有一个 JSON 数组：

[ {
  "account_login" : "[e-mail]","view_id" : 11313231,"join_id" : "utm_campaign=toyota&utm_content=multiformat_sites&utm_medium=cpc&utm_source=mytarget","start_date" : "2020-08-01","end_date" : "2020-08-31"
},{
  "account_login" : "[e-mail]","view_id" : 19556319183,"join_id" : "utm_campaign=mazda&utm_content=keywords_social-networks&utm_medium=cpc&utm_source=facebook","start_date" : "2020-12-22","end_date" : "2020-12-23"
},{
...
} ]

对于每个join_id，我应该做接下来的事情：

1. 将字符串拆分为键值对： utm_campaign,toyota; utm_content,multiformat_sites; etc
2. 过滤它们（下面的 Java 代码）；
3. 将密钥转换为另一种格式；使用数据库中的表（下面的 Java 代码）；

我的主要目标是重复这段 Java 代码：

public class GaUtmFactoryService {

    private static final String INVALID_MACRO_FOOTPRINTS = "^.*[{\\[%]+.+[}\\]%].*$";

    public Map<String,String> extractUtmMarks(String utmMarks) {
        if (utmMarks == null || utmMarks.isBlank()) {
            return Collections.emptyMap();
        }
        return Arrays.stream(utmMarks.split("\\s*&\\s*"))
                .map(s -> s.trim().split("\\s*=\\s*"))
                .filter(this::isUtmMarksValid)
                .collect(Collectors.toMap(
                        key -> convertCsUtmMarkToGa(key[0]),value -> value[1],(val1,val2) -> val2)
                );
    }

    
    private boolean isUtmMarksValid(String[] utmMarks) {
        return utmMarks.length == 2
                && !convertCsUtmMarkToGa(utmMarks[0]).isBlank()
                && !utmMarks[1].isBlank()
                && Arrays.stream(utmMarks).noneMatch(this::isUtmMarkContainsInvalidChars);
    }

    private boolean isUtmMarkContainsInvalidChars(String utmMark) {
        return utmMark.matches(INVALID_MACRO_FOOTPRINTS)
                || !StandardCharsets.US_ASCII.newEncoder().canEncode(utmMark);
    }

   
    private String convertCsUtmMarkToGa(String utmMark) {
       switch (utmMark) {
            case "utm_medium":
                return "ga:medium";
            case "utm_campaign":
                return "ga:campaign";
            case "utm_source":
                return "ga:source";
            case "utm_content":
                return "ga:adContent";
            case "utm_term":
                return "ga:keyword";
            case "utm_target":
            case "utm_a":
                return "";
            default:
                return rowUtmMarks;
        }
    }

}

外部使用：

public Map<String,String> getConvertedMarks() {
        GaUtmFactoryService gaUtmFactoryService = new GaUtmFactoryService();
        String utmMarks = "utm_campaign=toyota&utm_content=multiformat_sites&utm_medium=cpc&utm_source=facebook";
        Map<String,String> converted = gaUtmFactoryService.extractUtmMarks(utmMarks);
        //should be:
        ////{ga:campaign=toyota,ga:adContent=multiformat_sites,ga:medium=cpc,ga:source=facebook}
        return converted;
    }

NiFi 甚至有可能吗？或者，如果这很难，也许我应该为此任务创建带有一些端点的 REST 微服务？

更新

我做了 EvaluateJsonPath 和 SplitJson。现在每个 json 文件都有一个属性：utm.marks = utm_campaign=toyota&utm_content=multiformat_sites&utm_medium=cpc&utm_source=mytarget

我需要拆分这些属性并得到这样的结果：

campaign.key = ga:campaign

campaign.value = toyota

content.key = ga:content

content.value = multiformat_sites

等

解决方法

基于 daggett 一个 JSON（非数组）答案的解决方案：

import groovy.json.*
//get file from session
def ff=session.get()
if(!ff)return
//read stream,convert to reader,parse to list/objects

def data=ff.read().withReader("UTF-8"){r-> new JsonSlurper().parse(r) }
def builder = new JsonBuilder(data)

builder.content.join_id = builder.content.join_id.split("\\s*&\\s*")  //# to array
        .collectEntries{ 
                //# convert each item to map entry
                String[] kv = it.split("\\s*=\\s*")
                kv[0] = [
                    "utm_medium"   : "ga:medium","utm_campaign" : "ga:campaign","utm_source"   : "ga:source","utm_content"  : "ga:adContent","utm_term"     : "ga:keyword",].get( kv[0] )
                kv
            }
        .findAll{ k,v-> k } //# filter out empty/null keys
ff.write("UTF-8"){w-> builder.writeTo(w)}
//transfer to success
REL_SUCCESS<<ff