Android Room @insert，如何在创建数据库时插入带有列填充的行

如何解决Android Room @insert，如何在创建数据库时插入带有列填充的行

如果您传递单个 id 值，那么一切正常就不会出现错误。我通过当剩下的值为wordEn、wordRu时，输出错误： 没有为参数“wordEn”传递值 没有为参数“wordRu”传递值 如何在填充了列的数据库中插入一行？ 看看哪里

@Dao
interface WordDao {
@Insert(onConflict = OnConflictStrategy.IGNORE)            
    suspend fun insert(id: Word,wordEn: Word,wordRu: Word)
}

@Entity(tableName = "word_table")
data class Word (

    @PrimaryKey
    var id: Int,var wordEn: String,var wordRu: List<String>
)


@Database(entities = [Word::class],version = 1,exportSchema = false)
abstract class AppRoomDatabase : RoomDatabase() {

....
....
                    val instance = Room.databaseBuilder(
                        context.applicationContext,AppRoomDatabase::class.java,"app_room_database"
                    )
                        .addCallback(WordDatabaseCallback(scope))
                        .build()
                    INSTANCE = instance
                    instance
                }
        }
        private class WordDatabaseCallback(
            private val scope: CoroutineScope
        ) : RoomDatabase.Callback() {
           
            override fun onOpen(db: SupportSQLiteDatabase) {
                super.onOpen(db)
              
                INSTANCE?.let { database ->
                    scope.launch(Dispatchers.IO) {
                        populateDatabase(database.wordDao())
                    }
                }
            }
        }

        suspend fun populateDatabase(wordDao: WordDao) {
          
            //TEST Fill the database with random string
....
....
                var randomInt: Int = randomInt()
                var randomString: String = randomString()
                var list: List<String> = list()

                wordDao.insert(Word(randomInt,"$a _$randomString",list)) <- !!!
            }
            //TEST end
}

解决方法

插入语句不正确

@Dao
interface WordDao {
    @Insert(onConflict = OnConflictStrategy.IGNORE)            
    suspend fun insertWord(word: Word)

    @Insert(onConflict = OnConflictStrategy.IGNORE)            
    suspend fun insertWords(words: List<Word>)

    @Insert(onConflict = OnConflictStrategy.IGNORE)            
    suspend fun insertWords1(varargs words: Word)
}

由于 Word 是 entity

@Entity(tableName = "word_table")
data class Word (
    @PrimaryKey
    var id: Int,var wordEn: String,var wordRu: List<String>
)

Room ? Coroutines