如何解决SQL多重条件CASE WHEN和或
我加入了两个表(tbl1和tbl2)。两个表中都存在AnimalNo
,但这是tbl1的主键,并且可以在tbl2中多次出现(如果AnimalNo
与多个ConditionID
相关联)
tbl1
AnimalNo | KillDate
1 | 01/01/2019
2 | 01/01/2019
3 | 01/01/2019
4 | 01/01/2020
5 | 01/01/2020
tbl2
AnimalNo | ConditionID
1 | 1
1 | 2
2 | 1
3 | 1
3 | 2
4 | 1
5 | 1
5 | 2
在上面的示例中,我想要一个表,该表中我得到具有每种条件的AnimalID
的计数以及都具有AnimalNo
1和2的ConditionID
的计数:
Year | N_killed | Type1 | Type2 | Both
2019 | 3 | 3 | 2 | 2
2020 | 2 | 2 | 1 | 1
我有这个查询,可以成功告诉我每个单独的AnimalNo
的{{1}}的数量,但是我想添加最后一个称为ConditionID
的列,该列具有Both
同时具有AnimalNo
1和2
ConditionID
解决方法
我想这就是你想要的
SELECT
DATEPART(year,tbl1.KillDate) AS KillYear,COUNT(Distinct tbl1.AnimalNo) AS N_Killed,COUNT(CASE WHEN tbl2.ConditionId =9 THEN 1 END) AS Type1a,COUNT(CASE WHEN tbl2.ConditionId =75 THEN 1 END) AS Type1b,COUNT(CASE WHEN tbl2.ConditionId =23 THEN 1 END) AS Type2a,COUNT(CASE WHEN tbl2.ConditionId =81 THEN 1 END) AS Type2b,COUNT(CASE WHEN tbl2.ConditionId IN (9,75) OR tbl2.ConditionId IN (23,81) BothTypes
FROM tbl1 LEFT JOIN
tbl2 ON tbl1.AnimalNo = tbl2.AnimalNo
WHERE YEAR(tbl1.KillDate) >=2012
GROUP BY DATEPART(year,KillDate)
ORDER BY DATEPART(year,KillDate)
,
尝试一下:
declare @tbl1 table
(
AnimalNo int,KillDate date
)
insert into @tbl1(AnimalNo,KillDate)
select 1,'2019-01-01' union
select 2,'2019-01-01' union
select 3,'2019-01-01' union
select 4,'2020-01-01' union
select 5,'2020-01-01'
declare @tbl2 table
(
AnimalNo int,ConditionID int
)
insert into @tbl2(AnimalNo,ConditionID)
select 1,1 union
select 1,2 union
select 2,1 union
select 3,2 union
select 4,1 union
select 5,2
select
year(k.KillDate) as [Year],count(distinct k.AnimalNo) as N_Killed,sum(c.Type1),sum(c.Type2),sum(case when c.Type1 = 1 and c.Type2 = 1 then 1 else 0 end) as Both
from
@tbl1 k
JOIN
(
select
c.AnimalNo,max(case when c.ConditionID = 1 then 1 else 0 end) as Type1,max(case when c.ConditionID = 2 then 1 else 0 end) as Type2
from
@tbl2 c
group by c.AnimalNo
) c
on k.AnimalNo = c.AnimalNo
group by year(k.KillDate)
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