根据多个真实条件查询所有相同的ID

如何解决根据多个真实条件查询所有相同的ID

我有这张桌子：

id  act  st_dt    end_dt    stats
1   a    01/01/20 05/01/20  done
1   b    04/01/20 09/02/20  done 
1   c    09/02/20 null      not done 
1   d    09/02/20 09/02/20  done
2   a    09/03/19 14/05/20  done 
2   b    09/02/20 25/06/20  done 
2   c    01/03/20 22/03/20  done
2   d    09/02/20 null      not done 
3   a    11/05/20 13/09/19  done 
3   b    09/02/20 04/07/20  done
3   c    01/02/20 30/02/20  done 
3   d    11/02/20 24/02/20  done

我要查询具有活动a> = 01/01/20且活动d状态已完成的同一ID的所有活动“行为”， 因此结果应如下所示：

id  act  st_dt    end_dt    stats
1   a    01/01/20 05/01/20  done
1   b    04/01/20 09/02/20  done 
1   c    09/02/20 null      not done 
1   d    09/02/20 09/02/20  done

此ID满足两个条件，我这样做了：

select * from 
(
select 
 a.*,case when (act = 'a' and end_dt > to_date('01/01/20','dd/mm/yy')) and (act = 'd' and status = 'done') then 1 end) flag
from 
 table a 
)
where flag = 1; 

但它不会执行必需的操作，只会查询活动“ a”和“ d”

解决方法

您可以使用exists：

select a.*
from a
where exists (select 1
              from a a2
              where a2.id = a.id and a2.act = 'a' and a2.st_dt <= date '2020-01-01' 
             ) and
      exists (select 1
              from a a2
              where a2.id = a.id and a2.act = 'd' and a2.stats = 'done'
             ) ;
 

,

如果您想学习新知识：

创建表格：

USRegion

这是适用于12c及更高版本的解决方案

create table tab as 
with t (id,act,start_date,end_date,status) as
(
    select 1,'a',to_date('01/01/2020','dd/mm/yyyy'),to_date('05/01/2020','done' from dual union all
    select 1,'b',to_date('04/01/2020',to_date('09/02/2020','done'  from dual union all
    select 1,'c',null,'not done'  from dual union all
    select 1,'d','done' from dual union all
    select 2,to_date('09/03/2019',to_date('14/05/2020','done'  from dual union all
    select 2,to_date('25/06/2020',to_date('01/03/2020',to_date('22/03/2020','not done'  from dual union all
    select 3,to_date('11/05/2020',to_date('13/09/2019','done'  from dual union all
    select 3,to_date('04/07/2020','done' from dual union all
    select 3,to_date('01/02/2020',to_date('29/02/2020','done'  from dual union all --End_date is wrong in your input data I changed it to 29
    select 3,to_date('11/02/2020',to_date('24/02/2020','done' from dual
)
select * from t

,

首先进入两个子查询，分别是开工和做得好的作业的ID。

INTERSECT的结果可以同时获得两个条件的工作，并使用ID谓词中的IN集

查询

select *
from tab a
where id in (
  select id
  from tab a
  where (act = 'a' and st_dt >= to_date('01/01/20','dd/mm/yy')) 
 INTERSECT
  select id
  from tab a
  where (act = 'd' and stats = 'done')
)

,

一种选择是通过分析函数使用汇总条件，以确定是否同时满足两个条件：

WITH a2 AS
(
SELECT a.*,SUM(CASE WHEN act = 'a' AND end_dt >= date'2020-01-01'
                     THEN 1 
                     ELSE 0 
                      END) 
            OVER(PARTITION BY id) *
           SUM(CASE WHEN act = 'd' AND stats = 'done'
                               THEN 1 
                               ELSE 0 
                                END) 
                      OVER(PARTITION BY id) AS satisfies                         
  FROM a
)
SELECT id,st_dt,end_dt,stats
  FROM a2
 WHERE satisfies = 1

Demo