如何解决子对象通过信号/插槽从另一个线程发送
我有一个带有QChartView的窗口,该图表上可以显示很多序列。如果我将所有系列添加到主线程上,那么它可能会阻塞一段时间,因此出于性能原因,我想在另一个线程中创建QChart,在其中添加所有系列并将QChart通过信号发送到显示窗口。>
简化示例:
# This Python file uses the following encoding: utf-8
import sys
from PyQt5.QtCore import pyqtSignal,pyqtSlot,QThread,Qt,QMetaObject
from PyQt5.QtWidgets import QApplication,QMainWindow
from PyQt5.QtChart import QChart,QChartView,QLineSeries
import logging
class chart_window(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
self.resize(640,480)
chart = QChart()
self.chartview = QChartView(self)
self.chartview.setChart(chart)
self.setCentralWidget(self.chartview)
@pyqtSlot(QChart)
def on_chart_created(self,chart):
logging.debug("on_chart_created beg")
logging.debug("self.thread= {0}".format(self.thread()))
logging.debug("chartview.thread= {0}".format(self.chartview.thread()))
logging.debug("current thread= {0}".format(QThread.currentThread()))
logging.debug("chart.thread= {0}".format(chart.thread()))
# self.chartview.setChart(chart)
logging.debug("on_chart_created end")
class chart_creator(QThread):
chart_created = pyqtSignal(QChart)
@pyqtSlot()
def delayed_start(self):
self.start()
def run(self):
logging.debug("chart_creator.run beg")
chart = QChart()
series = QLineSeries()
series.setName("test")
series.append(0,10)
series.append(3,3)
series.append(6,8)
series.append(10,0)
chart.addSeries(series)
self.chart_created.emit(chart)
logging.debug("chart_creator.run end")
if __name__ == "__main__":
logging.basicConfig(format='%(asctime)s : %(levelname)s : %(message)s',level=logging.DEBUG)
app = QApplication([])
window = chart_window()
creator = chart_creator()
creator.chart_created.connect(window.on_chart_created)
window.show()
QMetaObject.invokeMethod(creator,"delayed_start",Qt.QueuedConnection)
sys.exit(app.exec_())
输出如下:
2020-09-18 16:03:07,299 : DEBUG : chart_creator.run beg
2020-09-18 16:03:07,304 : DEBUG : chart_creator.run end
2020-09-18 16:03:07,304 : DEBUG : on_chart_created beg
2020-09-18 16:03:07,305 : DEBUG : self.thread= <PyQt5.QtCore.QThread object at 0x000001B9E62293A8>
2020-09-18 16:03:07,306 : DEBUG : chartview.thread= <PyQt5.QtCore.QThread object at 0x000001B9E62293A8>
2020-09-18 16:03:07,306 : DEBUG : current thread= <PyQt5.QtCore.QThread object at 0x000001B9E62293A8>
2020-09-18 16:03:07,307 : DEBUG : chart.thread= <__main__.chart_creator object at 0x000001B9E6226A68>
2020-09-18 16:03:07,307 : DEBUG : on_chart_created end
因此要明确一点:在'on_chart_created'中接收到的'chart'与主窗口及其所有子级(0x000001B9E62293A8)处于不同的线程(0x000001B9E6226A68)中。结果,如果我尝试做self.chartview.setChart(chart)
,结果将是:
QObject: Cannot create children for a parent that is in a different thread.
(Parent is QTextDocument(0x1d45209f3b0),parent's thread is chart_creator(0x1d452022650),current thread is QThread(0x1d451bc14c0)
我尝试了moveToThread
,但实际上没有用,而且我没有其他解决方案。
那么stackoverflow社区中有人知道如何解决此问题吗?
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