如何解决更改屏幕并在kivyMD上运行功能?
我正在学习Kivy,但是我不知道如何同时切换屏幕和运行功能。
我应该在哪里声明我的功能,以便按钮可以访问代码并可以运行该功能?
from kivymd.app import MDApp
from kivy.lang.builder import Builder
from kivy.uix.screenmanager import ScreenManager,Screen
screen_helper = """
ScreenManager:
MenuScreen:
FunctionScreen:
<MenuScreen>:
name: 'menu'
MDRectangleFlatButton:
text: 'Function'
pos_hint: {'center_x':0.5,'center_y':0.5}
on_press: root.manager.current = 'function screen'
<FunctionScreen>:
name: 'function screen'
MDRectangleFlatButton:
text: 'Back'
pos_hint: {'center_x':0.5,'center_y':0.1}
on_press: root.manager.current = 'menu'
"""
class MenuScreen(Screen):
pass
class FunctionScreen(Screen):
pass
# Create the screen manager
sm = ScreenManager()
sm.add_widget(MenuScreen(name='menu'))
sm.add_widget(FunctionScreen(name='function'))
class DemoApp(MDApp):
def build(self):
screen = Builder.load_string(screen_helper)
return screen
# def funtion(self):
# do stuff and then go to menu screen
DemoApp().run()
我应该尝试在构建函数中添加on_opress属性吗?
你们能帮我吗?
解决方法
有几个方便的地方可以放置function()
。一个在MenuScreen
中,在这种情况下,它将在kv
文件中引用为:
root.function()
另一个方便的地方是DemoApp
,在这种情况下,引用将是:
app.function()
因此,这是您的代码的版本,将function()
放在App
中:
from kivymd.app import MDApp
from kivy.lang.builder import Builder
from kivy.uix.screenmanager import Screen
screen_helper = """
ScreenManager:
MenuScreen:
FunctionScreen:
<MenuScreen>:
name: 'menu'
MDRectangleFlatButton:
text: 'Function'
pos_hint: {'center_x':0.5,'center_y':0.5}
on_press:
root.manager.current = 'function screen'
app.function()
<FunctionScreen>:
name: 'function screen'
MDRectangleFlatButton:
text: 'Back'
pos_hint: {'center_x':0.5,'center_y':0.1}
on_press: root.manager.current = 'menu'
"""
class MenuScreen(Screen):
pass
class FunctionScreen(Screen):
pass
class DemoApp(MDApp):
def build(self):
sm = Builder.load_string(screen_helper)
return sm
def function(self):
# do stuff and then go to menu screen
print('in function')
DemoApp().run()
请注意,构建ScreenManager
的代码行已被删除,因为它们是不必要的。
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