查询以显示不同的组合，然后显示每个不同组合的计数

如何解决查询以显示不同的组合，然后显示每个不同组合的计数

此表中存在多个transid字段，其中包含配置值列表。对于所有的transid，我想按计数检索表组中存在的transid，config_name和value字段的所有不同组合

我有联接查询，该查询未按预期返回结果。下面是表结构，使用的查询，结果和预期结果

表

transid            config_name               value
1                   payment_fee                instant
2                   eligible_account           true
1                   Block_intl_trans           false
5                   payment_fee                provider_charge
1                   eligible_account           false  
1                         KycEligible               0
2                         KycEligible               1
5                        KycEligible                1
5                   Block_intl_trans            true
2                   Block_intl_trans            false   
2                   payment_fee                 provider_charge
5                   eligible_account            true 

上面的表结构意味着下面是每个用户的配置值的组合。

transid  KycEligible  payment_fee     eligible_account     Block_intl_trans
1      0            instant          false                false
2      1            provider_charge  true                 false
5      1            provider_charge  true                 false       

                   

下面是我用来将行转换为列然后按config_name分组的查询（对于每个config_name，而不是每个config键和值组合的多行）。然后选择表中存在的KycEligible，配置名称和值组合的所有不同组合以及每个不同组合的计数。

select
    distinct
    max(case when b.config_name = 'KycEligible' then b.config_value end) KycEligible,max(case when b.config_name = 'payment_fee' then b.config_value end)  payment_fee,max(case when b.config_name = 'eligible_account' then b.config_value end)  eligible_account,max(case when b.config_name = 'Block_intl_trans' then b.config_value end)  Block_intl_trans,count(*) AS COUNT
from tableA b
where b.config_name in ('KycEligible','payment_fee','eligible_account','Block_intl_trans')
group by b.config_name
having count(*) > 1

预期结果：

KycEligible  payment_fee     eligible_account     Block_intl_trans  Count
    0            instant          false                false             1
    1            provider_charge  true                 false             2 

我的查询未返回预期结果。有人可以帮忙这个查询吗？

解决方法

我认为您需要这样的东西：

stdout

这将给出以下内容：

SELECT
  KycEligible,payment_fee,eligible_account,Block_intl_trans,COUNT(*) CNT
FROM (
  SELECT
    (SELECT MAX(t0.config_value) FROM test t0 WHERE t0.config_name = 'KycEligible' AND t0.transid = t.transid) as KycEligible,(SELECT MAX(t0.config_value) FROM test t0 WHERE t0.config_name = 'payment_fee' AND t0.transid = t.transid) as payment_fee,(SELECT MAX(t0.config_value) FROM test t0 WHERE t0.config_name = 'eligible_account' AND t0.transid = t.transid) as eligible_account,(SELECT MAX(t0.config_value) FROM test t0 WHERE t0.config_name = 'Block_intl_trans' AND t0.transid = t.transid) as Block_intl_trans
  FROM
    test t
  GROUP BY t.transid
) dt
GROUP BY KycEligible,Block_intl_trans
;

结果与预期的不同之处在于：

ycEligible  payment_fee         eligible_account    Block_intl_trans    CNT
0           instant○            false               false                   1
1           provider_charge     true                false                   1
1           provider_charge     true                true                    1

,

我提供两个小提琴示例，因为您提供的示例数据不一致。

1. 此小提琴用于transid = 5，其中Block_intl_trans的数据为true-与您的表数据示例一致：https://www.db-fiddle.com/f/r1imsYP8dQxkLSo5SkYcVK/3
2. 此小提琴用于transid = 5，其中Block_intl_trans的数据为false-与您说明的配置组合一致：https://www.db-fiddle.com/f/r1imsYP8dQxkLSo5SkYcVK/4

我猜测唯一的组合将来自所有config_name值。这是查询示例：

SELECT KycEligible,COUNT(*) FROM
(SELECT transid,GROUP_CONCAT(CASE WHEN config_name="KycEligible" THEN config_value END) AS "KycEligible",GROUP_CONCAT(CASE WHEN config_name="payment_fee" THEN config_value END) AS "payment_fee",GROUP_CONCAT(CASE WHEN config_name="eligible_account" THEN config_value END) AS "eligible_account",GROUP_CONCAT(CASE WHEN config_name="Block_intl_trans" THEN config_value END) AS "Block_intl_trans"
 FROM TableA
 GROUP BY transid) V
GROUP BY KycEligible,Block_intl_trans;

,

使用Max的简单查询，
计算结果可以基于您的输入数据（transid = 5，config = Block_intl_trans，value = false或value = true）

SELECT KycEligible,COUNT(*) FROM
( 
SELECT 
       transid,max(CASE WHEN config_name="KycEligible" THEN value END) AS "KycEligible",max(CASE WHEN config_name="payment_fee" THEN value END) AS "payment_fee",max(CASE WHEN config_name="eligible_account" THEN value END) AS "eligible_account",max(CASE WHEN config_name="Block_intl_trans" THEN value END) AS "Block_intl_trans"
 FROM <YOUR_TABLE_NAME>
 GROUP BY transid
 ) tmp
GROUP BY KycEligible,Block_intl_trans;