移位值以找到给定纬度和经度的三个最接近的点

如何解决移位值以找到给定纬度和经度的三个最接近的点

我要查找给定经度和纬度的三个最接近的点作为输入，其中self.distance是被调用来进行计算的函数。这是我到目前为止的内容：

def closest_stations(self,latitude,longitude):
    loaded_json = self.status.json()
    first_closest = 0.00
    second_closest = 0.00
    third_closest = 0.00
    temp = 0.00
    temp2 = 0.00
    new_dict = {}
    for row in loaded_json['data']['stations']:
        row_lat = float(row["lat"])
        row_lon = float(row["lon"])
        distance = self.distance(latitude,longitude,row_lat,row_lon)
        temp_name = row["station_id"]
        temp_num = row['name']
        print(distance)
        if distance < first_closest or first_closest == 0.00: #first closest
            temp = first_closest
            temp2 = second_closest
            first_closest = distance
            second_closest = temp
            third_closest = temp2
            row_num1 = row["station_id"]
            row_name1 = row['name']
        elif (first_closest < distance < second_closest) or second_closest == 0.00: #between 1st and 2nd
            third_closest = second_closest
            second_closest = distance
            #row_num2 = row_num1
            #row_name2 = row_name1
            row_num2 = row["station_id"]
            row_name2 = row['name']
        elif (second_closest < distance < third_closest) or third_closest == 0.00: #between 2nd and 3rd
            third_closest = distance
            row_num3 = row["station_id"]
            row_name3 = row['name']
        print(first_closest,second_closest,third_closest)
    new_dict ={row_num1: row_name1,row_num2: row_name2,row_num3: row_name3}
    return new_dict

我有逻辑找到三个最接近的距离，并且发现我的代码正正确地找到最短的距离，如图像enter image description here所示。最上面的数字是计算出的距离，而三个是要替换的数字（依此类推）。我遇到的麻烦是，我需要返回一个字典，其中station_id映射到我要用作row ['station_id]和row ['name']的站点名称。这是我需要帮助的部分，想知道是否有人可以给我指点。我知道如何随着距离“移动”，但是我不确定如何通过字典值本身来做到这一点。

例如，假设我们有最短的距离1,4和6，并引入了新的距离3。在这种情况下，3将替换4，而4将向右移动。我知道如何使用距离来做到这一点，从而使3个最短距离成为：1、3和4。但是，我完全不知道如何对字典进行移位。