我正在努力使用Django queryset使具有多条件的搜索功能

如何解决我正在努力使用Django queryset使具有多条件的搜索功能

#root p.buffer {
    display: block;
}

urls.py

def influencer_board(request):
    user_input = []
    index_list = []
    influencer = Influencer_DB.objects.all()
    if request.method == 'GET':
        sns_type = request.GET.get('sns_type') #0
        follower_num_min = request.GET.get('follower_num_min') #1
        follower_num_max = request.GET.get('follower_num_max') #2
        name = request.GET.get('name')#3
        gender = request.GET.get('gender')#4
        sns_id = request.GET.get('sns_id')#5
        keyword = request.GET.get('keyword')#6

        user_input.append(sns_type)
        user_input.append(follower_num_min)
        user_input.append(follower_num_max)
        user_input.append(name)
        user_input.append(gender)
        user_input.append(sns_id)
        user_input.append(keyword)

        for col in user_input:
            if col != "":
                index = user_input.index(col)
                index_list.append(index)

        influencer = Influencer_DB.objects
        for index in index_list:
            if index == 0:
                influencer = influencer.filter(sns_type=sns_type)
            if index == 1:
                influencer = influencer.filter(follower_num__gte = follower_num_min)
            if index == 2:
                influencer = influencer.filter(follower_num__lte = follower_num_max)
            if index == 3:
                influencer = influencer.filter(name=name)
            if index == 4:
                influencer = influencer.filter(gender = gender)
            if index == 5:
                influencer = influencer.filter(sns_id=sns_id)
            if index == 6:
                influencer = influencer.filter(keyword__icontains = keyword)

        return render(request,"influencer_board.html",{'influencer':influencer,"sns_type":sns_type,'follower_num_max':follower_num_max,'followever':follower_num_min,'name':name,'gender':gender,'sns_id':sns_id,'keyword':keyword})
    return render(request,{'influencer':influencer})

像上面的代码一样，我从用户那里得到7个搜索条件。另外，如果用户输入的条件少于7个，我仍然希望使用这些条件过滤数据库。但是，它不断出现此错误：

该功能似乎可以正常运行，因为网址

from django.contrib import admin
from django.urls import path,include
from main.views import main,go_back_and_clean,create_contract,show_record,confirm,delete,wait,delete_contract,celly_btn_info,btn_push,btn_create,btn_delete
from main.views import btn_condition_change
from login.views import login,logout,signup
from influencer_db.views import influencer_board

urlpatterns = [
    path('admin/',admin.site.urls),path('home/',main,name='home'),path('delete/',name="delete"),path('',login,name='login'),path('logout/',name='logout'),path('sign_up/',signup,name='signup'),path('create_contract/',name='create_contract'),path('contract_board/<int:contract_id>',name='contract_board'),path('confirm/<int:record_id><int:contract_id>',name='confirm'),path('delete/<int:record_id><int:contract_id>',name='delete'),path('wait/<int:record_id><int:contract_id>',name='wait'),path('delete_contract/<int:contract_id>',name='delete_contract'),path('btn_info/<int:btn_id>',name='btn_info'),path('btn_push/<int:btn_id>',name="btn_push"),path('btn_create/',name='btn_create'),path('btn_delete/<int:btn_id>',btn_delete,name='btn_delete'),path('btn_condition_change/<int:btn_id>',btn_condition_change,name='btn_condtion_change'),path('influencer_board/',influencer_board,name="internal_influencer"),

包含我提交的条件，但出现404错误。我该如何解决这个问题？

解决方法

可以减少和简化您的视图代码。所有7个字段都具有相似的过滤逻辑，因此我们可以构建要过滤的字段列表（包括它们的字段过滤器，例如__gte和FILTER_KEYS = ( ('sns_type','sns_type'),('follower_num_min','follower_num__gte'),('follower_num_max','follower_num__lte'),('name','name'),('gender','gender'),('sns_id','sns_id'),('keyword','keyword__icontains'),) def influencer_board(request): qs = Influencer_DB.objects.all() ctx = {} if request.method == 'GET': for key,field_with_filter in FILTER_KEYS: v = request.GET.get(key,'').strip() if len(v) == 0: # it's empty,so skip this continue # filter the QuerySet qs = qs.filter(**{field_with_filter: v}) # add to context for template rendering ctx[key] = v # add to context for template rendering ctx['influencer'] = qs return render(request,"influencer_board.html",ctx) ）并遍历该列表，而不用写几乎相同的东西7次

这里建议应该以更少的代码实现相同的功能。

private void btn_Approve_ButtonClick(object sender,DevExpress.XtraEditors.Controls.ButtonPressedEventArgs e)
    
    {
      
          
        gridView1.SetRowCellValue(gridView1.FocusedRowHandle,gridView1.Columns["UO_APR_STS"],"A");

        var a=  gridView1.GetFocusedRowCellValue("UO_SYS_ID");
        double ab = double.Parse(a.ToString());

        BindingList<OM_UNIT_OFFER> result = new BindingList<OM_UNIT_OFFER>((from u in Program.projectModel.OM_UNIT_OFFERS
                                                                            orderby u.UO_SYS_ID
                                                                            where u.UO_SYS_ID == ab
                                                                            select u).ToList());
        

        if (gridView1.PostEditor())
        {

        OM_UNIT_OFFER _unif = new OM_UNIT_OFFER();
        _unif.UO_APR_STS = "A";
        gridView1.FocusedColumn = gridView1.Columns["_unif.UO_APR_STS"];
        gridView1.UpdateCurrentRow();

        }
        
        gridView1.ShowEditor();
      
    }         




private void gridView1_RowUpdated(object sender,RowObjectEventArgs e)
    {            
     Program.projectModel.SaveChangesAsync();
    }