使用JavaScript更新重复项

如何解决使用JavaScript更新重复项

我得到两个对象数组进行比较并返回一个结果，该结果包含两个数组，一个用于插入，另一个用于更新。

• aObj->父对象。 （主键/唯一键为空）
• bObj->子对象。（主键/唯一键为Empid）

let a = [
  { empid: "emp001",name: "test1",status: "emp" },{ empid: "emp002",name: "test2",status: "ex-emp" },{ empid: "emp003",name: "test3",status: "emp" }
];

let b = [
  { empid: "emp001",name: "test1_updated",status: "emp" }
];

//insert array
// console.log(_.differenceBy(a,b,'empid'));

//update array
let updateArr = [],insertArr = [];
for (let i = 0; i < a.length; i++) {
  let aObj = a[i];
  for (let j = 0; j < b.length; j++) {
    let bObj = b[j];
    if (aObj.empid === bObj.empid) {
      if (aObj.status !== bObj.status || aObj.name !== bObj.name) {
        updateArr.push(aObj);
      }
    } else {
      insertArr.push(aObj);
    }
  }
}
console.log("--update--");
console.log(updateArr);
console.log("--insert--");
console.log(insertArr);

代码链接-https://codesandbox.io/s/fervent-kare-ixht9?fontsize=14&hidenavigation=1&theme=dark

解决方法

使用_.differenceBy()中的empid获取插入数组，并使用_.intersectionWith()查找具有相同empid的不相等项。

const a = [
  { empid: "emp001",name: "test1",status: "emp" },{ empid: "emp002",name: "test2",status: "ex-emp" },{ empid: "emp003",name: "test3",status: "emp" }
];

const b = [
  { empid: "emp001",name: "test1_updated",status: "ex-emp" } // equals to emp002
];

const updateArr = _.intersectionWith(a,b,(a,b) => a.empid === b.empid && !_.isEqual(a,b));
const insertArr = _.differenceBy(a,'empid');

console.log("--update--");
console.log(updateArr); // emp001
console.log("--insert--");
console.log(insertArr); // emp003

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.20/lodash.min.js" integrity="sha512-90vH1Z83AJY9DmlWa8WkjkV79yfS2n2Oxhsi2dZbIv0nC4E6m5AbH8Nh156kkM7JePmqD6tcZsfad1ueoaovww==" crossorigin="anonymous"></script>