Mysql多对多关系，将结果显示在一行中

如何解决Mysql多对多关系，将结果显示在一行中

请帮助我，我已经尝试过，但是找不到正确的答案。我有5张桌子users,profile,questions,question_responses and profile_responses。用户必须提供诸如以下问题的答案

地区（安大略省，不列颠哥伦比亚省等）
种族（白人，中国人，南亚人等）
类型（食品，健康，时尚等）
国家（加拿大，英国，美国）。

profile_responses表与配置文件，响应和profile_responses有许多关系。下表是这些表。

CREATE TABLE `users` (
  `id` int(11) NOT NULL,'email' varchar(300) NOT NULL,'password' varchar(300) NOT NULL,'name' varchar(300) NOT NULL,'user_type' varchar(10) NOT NULL,);

INSERT INTO `users` (`id`,`email`,`password`,`name`,`user_type`) VALUES 
(8,'test1@gmail.com','','Test Name1','Influencers'),(14,'Test Name2',(15,'Test Name3','Influencers');



CREATE TABLE `profile` (
  `id` int(11) NOT NULL,`user_id` int(11) NOT NULL,`name` varchar(500) NOT NULL,`instagram_handle` varchar(1000) NOT NULL,`comments` text NOT NULL
);
 
INSERT INTO `profile` (`id`,`user_id`,`instagram_handle`,`comments`) VALUES
(1,8,'testhandle1','Test Comments'),(10,14,'testhandle2',(12,15,'Test Name3 ','testhandle3','Test Comments');



questions
CREATE TABLE `questions` (
  `id` int(11) NOT NULL,`text` varchar(50) NOT NULL,`active` int(11) NOT NULL
);
 
INSERT INTO `questions` (`id`,`text`,`active`) VALUES
(1,'country',1),(2,'ethnicity',(3,'region',(4,'genre',1);



question_responses
CREATE TABLE `question_responses` (
  `id` int(11) NOT NULL,`question_id` int(11) NOT NULL,`text` varchar(300) NOT NULL,`abbr` varchar(30) NOT NULL,`active` tinyint(4) NOT NULL,);

INSERT INTO `question_responses` (`id`,`question_id`,`abbr`,`active`,`sort_order`) VALUES
(1,1,'USA','US',0),'UK','Canada','CA',(7,2,'South Asian','SA',(8,'Chinese','CH',(9,'White','W',(13,4,'Lifestyle','Fashion','Food',(16,'Health & Fitness','Health',(18,3,'Britich Columbia','BC',6),(19,'Ontario','ON',(20,'Alberta','AB',9),(23,'Taxes','TX',52),(24,'California',15);


profile_responses
CREATE TABLE `profile_responses` (
  `id` int(11) NOT NULL,`response_id` int(11) NOT NULL,FOREIGN KEY (user_id) REFERENCES profile(user_id) ON UPDATE CASCADE,FOREIGN KEY (response_id) REFERENCES question_responses(id) ON UPDATE CASCADE
);

INSERT INTO `profile_responses` (`id`,`response_id`) VALUES 
(1,3),18),15),(5,(6,23),16),19),(11,14),7);

我试图像下面这样在一行中显示每个用户的回复

Name            Region      Ethnicity           Genre                   Country
Test Name1      BC              White           Food                    Canada
Test Name2      Taxes           White           Health & Fitness        USA
Test Name3      Ontario         South Asian     Fashion                 Canada

对于该解决方案，我创建了两个查询。首先，我确定有多少用户回答了问题。由于响应变化，因此N（具有计数）基于响应集。该查询工作正常。

SELECT pro.user_id
FROM profile_responses as pr
INNER JOIN profile as pro ON pro.user_id = pr.user_id
WHERE pr.response_id IN (3,18,23,16,19,7) 
GROUP BY pro.user_id
HAVING COUNT(DISTINCT pr.response_id) >= N

为了显示结果，我尝试了以下有效的方法，但是如果我有10个问题，那么我必须写10个组合吗？请帮助我，我不是专家。

select us1.id,us1.email,up1.name,up1.instagram_handle,qr.abbr as region,qr1.abbr as ethnicity,up1.followers,qr2.abbr as genre,qr3.abbr as country,up1.comments
FROM users as us1
LEFT JOIN profile as up1 ON up1.user_id = us1.id

LEFT JOIN profile_responses usrep ON up1.user_id = usrep.user_id 
JOIN question_responses qr ON usrep.response_id = qr.id AND qr.question_id = 3
JOIN questions qs ON qs.id = qr.question_id

LEFT JOIN profile_responses usrep1 ON up1.user_id = usrep1.user_id 
JOIN question_responses qr1 ON usrep1.response_id = qr1.id AND qr1.question_id = 2
JOIN questions qs1 ON qs1.id = qr1.question_id

LEFT JOIN profile_responses usrep2 ON up1.user_id = usrep2.user_id 
JOIN question_responses qr2 ON usrep2.response_id = qr2.id AND qr2.question_id = 4
JOIN questions qs2 ON qs2.id = qr2.question_id

LEFT JOIN profile_responses usrep3 ON up1.user_id = usrep3.user_id 
JOIN question_responses qr3 ON usrep3.response_id = qr3.id AND qr3.question_id = 1
JOIN questions qs3 ON qs3.id = qr3.question_id

WHERE us1.user_type="Influencers" AND us1.id IN (8,15)
GROUP BY us1.id

Mysql多对多关系，将结果显示在一行中

如何解决Mysql多对多关系，将结果显示在一行中

相关推荐