太多值无法解压缩预期3个pygame点击问题

如何解决太多值无法解压缩预期3个pygame点击问题

我目前正在从事CS50项目，研究井字游戏所需的AI。但是我无法运行Runner.py文件，因为出现以下错误：

回溯（最近通话最近）：文件 “ /Users/newtracksuit/Downloads/tictactoe/runner.py”，第57行，在 click，_，_ = pygame.mouse.get_pressed（）ValueError：太多值无法解包（预期3）

这是提供的完整代码，我尚未为tic-tac-toe程序编写任何实际功能，只需要了解为什么这还行不通

import pygame
import sys
import time

import tictactoe as ttt

pygame.init()
size = width,height = 600,400

# Colors
black = (0,0)
white = (255,255,255)

screen = pygame.display.set_mode(size)

mediumFont = pygame.font.Font("OpenSans-Regular.ttf",28)
largeFont = pygame.font.Font("OpenSans-Regular.ttf",40)
moveFont = pygame.font.Font("OpenSans-Regular.ttf",60)

user = None
board = ttt.initial_state()
ai_turn = False

while True:

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            sys.exit()

    screen.fill(black)

    # Let user choose a player.
    if user is None:

        # Draw title
        title = largeFont.render("Play Tic-Tac-Toe",True,white)
        titleRect = title.get_rect()
        titleRect.center = ((width / 2),50)
        screen.blit(title,titleRect)

        # Draw buttons
        playXButton = pygame.Rect((width / 8),(height / 2),width / 4,50)
        playX = mediumFont.render("Play as X",black)
        playXRect = playX.get_rect()
        playXRect.center = playXButton.center
        pygame.draw.rect(screen,white,playXButton)
        screen.blit(playX,playXRect)

        playOButton = pygame.Rect(5 * (width / 8),50)
        playO = mediumFont.render("Play as O",black)
        playORect = playO.get_rect()
        playORect.center = playOButton.center
        pygame.draw.rect(screen,playOButton)
        screen.blit(playO,playORect)

        # Check if button is clicked
        click,_,_ = pygame.mouse.get_pressed()
        if click == 1:
            mouse = pygame.mouse.get_pos()
            if playXButton.collidepoint(mouse):
                time.sleep(0.2)
                user = ttt.X
            elif playOButton.collidepoint(mouse):
                time.sleep(0.2)
                user = ttt.O

    else:

        # Draw game board
        tile_size = 80
        tile_origin = (width / 2 - (1.5 * tile_size),height / 2 - (1.5 * tile_size))
        tiles = []
        for i in range(3):
            row = []
            for j in range(3):
                rect = pygame.Rect(
                    tile_origin[0] + j * tile_size,tile_origin[1] + i * tile_size,tile_size,tile_size
                )
                pygame.draw.rect(screen,rect,3)

                if board[i][j] != ttt.EMPTY:
                    move = moveFont.render(board[i][j],white)
                    moveRect = move.get_rect()
                    moveRect.center = rect.center
                    screen.blit(move,moveRect)
                row.append(rect)
            tiles.append(row)

        game_over = ttt.terminal(board)
        player = ttt.player(board)

        # Show title
        if game_over:
            winner = ttt.winner(board)
            if winner is None:
                title = f"Game Over: Tie."
            else:
                title = f"Game Over: {winner} wins."
        elif user == player:
            title = f"Play as {user}"
        else:
            title = f"Computer thinking..."
        title = largeFont.render(title,30)
        screen.blit(title,titleRect)

        # Check for AI move
        if user != player and not game_over:
            if ai_turn:
                time.sleep(0.5)
                move = ttt.minimax(board)
                board = ttt.result(board,move)
                ai_turn = False
            else:
                ai_turn = True

        # Check for a user move
        click,_ = pygame.mouse.get_pressed()
        if click == 1 and user == player and not game_over:
            mouse = pygame.mouse.get_pos()
            for i in range(3):
                for j in range(3):
                    if (board[i][j] == ttt.EMPTY and tiles[i][j].collidepoint(mouse)):
                        board = ttt.result(board,(i,j))

        if game_over:
            againButton = pygame.Rect(width / 3,height - 65,width / 3,50)
            again = mediumFont.render("Play Again",black)
            againRect = again.get_rect()
            againRect.center = againButton.center
            pygame.draw.rect(screen,againButton)
            screen.blit(again,againRect)
            click,_ = pygame.mouse.get_pressed()
            if click == 1:
                mouse = pygame.mouse.get_pos()
                if againButton.collidepoint(mouse):
                    time.sleep(0.2)
                    user = None
                    board = ttt.initial_state()
                    ai_turn = False

    pygame.display.flip()

解决方法

pygame.mouse.get_pressed()

返回代表所有鼠标按钮状态的布尔值序列。

按钮的数量是4或6，这取决于pygame的版本。我建议按订阅获取单个按钮的状态：

buttons = pygame.mouse.get_pressed()
if button[0] == 1:
    # [...]

,

执行pygame.mouse.get_pressed()时返回什么？我看到(0,0)是您的代码期望的三个参数。

您可以计算出代码返回的内容并添加必要数量的下划线，但是如果您对其余参数不感兴趣，则可以使用*处理其余的返回值，例如

click,*_ = pygame.mouse.get_pressed()