如何解决如何在JSON根节点中添加键值对并将其转换为使用SQL Server的表
我有桌子工作人员,它维护着四个列,分别是Name,TagName,Value和Location。 我想使用名称和位置列作为根节点转换json中的标记名和值(多个记录的名称和位置相同)
需要输出为:
{
"{"Name":"EMP1","Location":"mumbai"}": [
{
"TagName": "1","Value": "844.17769999999996"
},{
"TagName": "abc","Value": "837.43679999999995"
},{
"TagName": "pqr","Value": "0"
},{
"TagName": "XYZ","Value": "1049.2429999999999"
}
]
}
请检查以下查询,我试图在其中使用json路径创建json字符串,但卡在根节点中。
SELECT TagName,Value
FROM dbo.people
FOR JSON PATH,ROOT('')---
当我将上述json转换为表格格式时,要求输出为:
Name | Location |TagName| Value
EMP1 | Mumbai |1 | 844.17769999999996|
EMP1 | Mumbai |abc | 837.43679999999995|
.....
解决方法
您的预期输出不是有效的JSON,但是您可能正在寻找类似这样的内容:
表格:
CREATE TABLE People (
[Name] varchar(10),[Location] varchar(50),[TagName] varchar(3),[Value] numeric(20,14)
)
INSERT INTO People ([Name],[Location],[TagName],[Value])
VALUES
('EMP1','Mumbai','1',844.17769999999996),('EMP1','abc',837.43679999999995),('EMP2',837.43679999999995)
声明:
SELECT DISTINCT p.[Name],p.[Location],c.Items
FROM People p
CROSS APPLY (
SELECT [TagName],[Value]
FROM People
WHERE [Name] = p.[Name] AND [Location] = p.[Location]
FOR JSON AUTO
) c (Items)
FOR JSON PATH
结果:
[
{
"Name":"EMP1","Location":"Mumbai","Items":[
{
"TagName":"1","Value":844.17769999999996
},{
"TagName":"abc","Value":837.43679999999995
}
]
},{
"Name":"EMP2","Items":[
{
"TagName":"abc","Value":837.43679999999995
}
]
}
]
如果要解析生成的JSON,则需要使用两次OPENJSON()
:
生成的JSON:
DECLARE @json varchar(max) = N'[
{
"Name":"EMP1","Value":837.43679999999995
}
]
}
]'
声明:
SELECT j1.Name,j1.Location,j2.TagName,j2.Value
FROM OPENJSON(@json) WITH (
[Name] varchar(10) '$.Name',[Location] varchar(50) '$.Location',[Items] nvarchar(max) '$.Items' AS JSON
) j1
OUTER APPLY OPENJSON(j1.Items) WITH (
[TagName] varchar(3) '$.TagName',14) '$.Value'
) j2
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。