如何解决SQL查询将列名更改为单列值
我正在使用SQL Server。不知道是哪个版本,但仍受支持。 我有一个表,该表包含我感兴趣的3列。我需要更改“硬件”列中的列名称以及每个列的计数。现在,我有以下内容:
SELECT
COUNT(a.EAMacBook13) AS 'MacBook13',COUNT(a.EAMacBook16) AS 'MacBook16',COUNT(a.EAStandLaptop) AS 'StandLaptop'
FROM
Employee AS e,EmpAttributes AS a
WHERE
a.EAEmpID = e.EmpID AND e.EmpProjID = 1
相反,我需要类似的东西:
这可能吗?
解决方法
基本思想是取消计数。如果您的数据库支持横向联接(也称为cross apply
)和values()
,则可以执行以下操作:
select x.hardware,count(x.val) cnt
from employee as e
inner join empattributes as ea on ea.eaempid = e.empid
cross join lateral (values
('EAMacBook13',ea.EAMacBook13),('EAMacBook16',ea.EAMacBook16),('EAStandLaptop',ea.EAStandLaptop)
) x(hardware,val)
where e.empprojid = 1
group by x.hardware
根据您的数据库,横向连接可以使用不同的语法。某些数据库使用cross apply
而不是cross join lateral
。
values()
也并非在所有地方都受支持。例如,在Oracle中,您可以将横向联接的短语设置为:
cross apply (
select 'EAMacBook13' as hardware,EAMacBook13 as val from dual
union all select 'EAMacBook16',EAMacBook16 from dual
union all select 'EAStandLaptop',EAStandLaptop from dual
) x(hardware)
如果以上方法均不可用,那么我们可以退回到union all
:
select x.hardware,count(x.val) cnt
from employee as e
inner join (
select eaempid,'EAMacBook13' as hardware,EAMacBook13 as value from empattributes
union all select eaempid,'EAMacBook16',EAMacBook16 from empattributes
union all select eaempid,'EAStandLaptop',EAStandLaptop from empattributes
) x on x.eaempid = e.empid
where e.empprojid = 1
group by x.hardware
,
您可以通过简单的全部合并来实现:
SELECT 'MacBook13' "Hardware",Count(a.EAMacBook13) "Count"
FROM Employee as e,EmpAttributes as a WHERE a.EAEmpID = e.EmpID and e.EmpProjID = 1
union all
SELECT 'MacBook16' "Hardware",Count(a.EAMacBook16) "Count"
FROM Employee as e,EmpAttributes as a WHERE a.EAEmpID = e.EmpID and e.EmpProjID = 1
union all
SELECT 'StandLaptop' "Hardware",Count(a.EAStandLaptop) "Count"
FROM Employee as e,EmpAttributes as a WHERE a.EAEmpID = e.EmpID and e.EmpProjID = 1
根据您的RDBMS,您可能可以访问UNPIVOT,从而减少编写工作。
您还可以使用CTE,以便(如果RDBMS支持实现它们)您可以减少工作量:
with cte as (
SELECT Count(a.EAMacBook13) as EAMacBook13,Count(a.EAMacBook16) as EAMacBook16,Count(a.EAStandLaptop) as EAStandLaptop
FROM Employee as e,EmpAttributes as a WHERE a.EAEmpID = e.EmpID and e.EmpProjID = 1
)
SELECT 'MacBook13' "Hardware",EAMacBook13 "Count"
FROM cte
union all
SELECT 'MacBook16' "Hardware",MacBook16 "Count"
FROM cte
union all
SELECT 'StandLaptop' "Hardware",StandLaptop "Count"
FROM cte
除非使用某种程度的动态SQL,否则您必须列出可能的硬件值。
,一个选项是使用“动态取消旋转”。首先使用当前查询创建一个表:
SELECT a.EAMacBook13,a.EAMacBook16,a.EAStandLaptop
INTO tab
FROM Employee AS e
JOIN EmpAttributes AS a
ON a.EAEmpID = e.EmpID
WHERE e.EmpProjID = 1
然后使用information_schema.columns
:
DECLARE @cols AS NVARCHAR(MAX),@query AS NVARCHAR(MAX)
SET @query =
(SELECT STRING_AGG(CONCAT('SELECT ''',SUBSTRING(column_name,3,LEN(column_name)),''' AS Hardware,COUNT(',column_name,') AS Count FROM tab '),' UNION ALL ')
FROM information_schema.columns
WHERE table_name = 'tab');
EXEC sp_executesql @query;
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。