如何使用grepl搜索字符串中的最大和最小计时?

如何解决如何使用grepl搜索字符串中的最大和最小计时?

我有一个数据集,该数据集的列包含各种商店的营业时间和营业时间。 时间采用字符串格式开启时间-关闭时间, 例如:17:00-21:00 | 11:30-14:30 | 11:30-14:30

我想提取上述字符串中的最小打开时间(即11:30)和最大关闭时间(即21:00),如何使用R做到这一点?

DPUT:

 structure(list(head.timings_remapping.Opening.And.Closing.Time..40. = c("15:30 - 21:30","12:00 - 00:00","11:00 - 15:00 | 16:30 - 20:45","12:00 - 22:30","17:00 - 21:30","16:30 - 00:00","16:00 - 21:15","16:30 - 20:30","17:00 - 20:00","16:00 - 23:30","16:30 - 21:30","17:00 - 22:00","16:00 - 00:00","16:30 - 23:59","11:30 - 22:30","11:30 - 23:59","17:00 - 20:30","07:30 - 12:50","16:15 - 23:00","09:00 - 21:00","10:00 - 21:00","11:00 - 22:00","07:00 - 12:00 | 07:00 - 13:30 | 12:00 - 13:30","07:00 - 13:00 | 10:00 - 15:00","10:00 - 02:00","00:00 - 23:59","11:00 - 20:00",NA,"12:00 - 03:30 | 11:00 - 00:00","05:30 - 15:00","07:00 - 16:00","08:30 - 13:30","17:00 - 21:00 | 11:30 - 14:30 | 11:30 - 14:30","12:00 - 01:00")),class = "data.frame",row.names = c(NA,-40L
))

最终输出将有两列“开放时间”和“结束时间”

解决方法

这项工作:

library(dplyr)
library(tidyr)
df %>% 
   separate(col = head.timings_remapping.Opening.And.Closing.Time..40.,into = c('Open_Close','A'),sep = '\\|') %>% 
   separate(col = Open_Close,into = c('Opening Time','Closing Time'),sep = ' - ') %>% 
   mutate(`Opening Time` = trimws(`Opening Time`),`Closing Time` = trimws(`Closing Time`)) %>% select(-A)
   Opening Time Closing Time
1         15:30        21:30
2         12:00        00:00
3         11:00        15:00
4         12:00        22:30
5         17:00        21:30
6         17:00        21:30
7         16:30        00:00
8         16:00        21:15
9         16:30        20:30
10        17:00        20:00
11        16:00        23:30
12        16:30        21:30
13        17:00        22:00
14        17:00        22:00
15        17:00        21:30
16        17:00        21:30
17        16:00        00:00
18        16:30        23:59
19        11:30        22:30
20        11:30        23:59
21        17:00        20:30
22        07:30        12:50
23        16:15        23:00
24        09:00        21:00
25        10:00        21:00
26        11:00        22:00
27        07:00        12:00
28        07:00        13:00
29        10:00        02:00
30        00:00        23:59
31        00:00        23:59
32        11:00        20:00
33        11:00        20:00
34         <NA>         <NA>
35        12:00        03:30
36        05:30        15:00
37        07:00        16:00
38        08:30        13:30
39        17:00        21:00
40        12:00        01:00
 
,

使用dplyrtidyr库,您可以执行以下操作:

library(dplyr)
library(tidyr)

#Rename the long column name to something smaller
names(df)[1] <- 'Time'

df %>%
  #Create a row index
  mutate(row = row_number()) %>%
  #Split the data in different rows on '|'
  separate_rows(Time,sep = '\\s*\\|\\s*') %>%
  #split the data on '-'
  separate(Time,c("Opening_Time","Closing_time"),sep = '\\s*-\\s*') %>%
  #Change the time to POSIXct format
  mutate(across(c(Opening_Time,Closing_time),as.POSIXct,format = '%H:%M')) %>%
  #For each row
  group_by(row) %>%
  #Get minimum opening time and maximum closing time 
  #and change into required format
  summarise(Opening_Time = format(min(Opening_Time),"%H:%M"),Closing_time = format(max(Closing_time),"%H:%M")) %>%
  #Drop row column
  select(-row)

这将返回

#  Opening_Time Closing_time
#   <chr>        <chr>       
# 1 15:30        21:30       
# 2 12:00        00:00       
# 3 11:00        20:45       
# 4 12:00        22:30       
# 5 17:00        21:30       
# 6 17:00        21:30       
# 7 16:30        00:00       
# 8 16:00        21:15       
# 9 16:30        20:30       
#10 17:00        20:00       
# … with 30 more rows

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