如何使用Mongoose返回所有子文档

如何解决如何使用Mongoose返回所有子文档

我正在使用猫鼬，并且想访问子文档中的所有子文档。简而言之，我想返回存储在诊所文档中的牙医子文档中的所有 booking 子文档。

现在，我的解决方案包含很多循环，但是必须有更好的方法。下面的代码有效并描述了我的野心。如果愿意，我愿意重新安排架构结构。请帮助我改进它。

router.post('/available-times',function (req,res) {
  let available_times = [];
  Clinic.find()
  .then((clinics)=> {
    clinics.forEach((clinic) => { 
      clinic.dentists.forEach((dentist) => {
        dentist.schedule.forEach((booking) => {
          if(!booking.reserved){
            available_times.push(booking)
          }
        })
      })
    });
    const response = {
          success: true,result: available_times,}
        res.json(response)
      })
      .catch(err => res.status(400).json("Error: " + err));
})

诊所模式：

const clinicSchema = new Schema({
    address:                            { type: String},clinic_name:                        { type: String},contact_person:                     { type: String},dentists:                           [Dentist.schema],description:                        { type: String},email:                              { type: String},isVerified:                         { type: Boolean,default: false },location:                           { type: String},logo_url:                           { type: String},});

牙医模式：

const dentistSchema = new Schema({
    biography:              { type: String},languages_spoken:       [String],name:                   { type: String},offered_services:       [String],picture_url:            { type: String},reviews:                { type: Array},schedule:               [Booking.schema],});

预订模式：

const bookingSchema = new Schema({
    title:              { type: String},start:              { type: Date},end:                { type: Date},customer_email:     { type: String},customer_name:      { type: String},customer_phone:     { type: String},dentist_id:         { type: String},dentist_name:       { type: String},clinic_id:          { type: String},price:              { type: Number},reserved:           { type: Boolean,});

解决方法

我猜集合Clinic的结构看起来像这样

[
    {
        _id: ObjectId('5fa36e4d0e5796a0221bad0d'),dentists: [
            {schedule: [{booking: {reserved: true,foo: 'bar1'}}]},{
                schedule: [
                    {booking: {reserved: false,foo: 'bar2'}},{booking: {reserved: true,foo: 'bar3'}}
                ]
            }
        ]
    },{
        _id: ObjectId('5fa373340e5796a0221bad0e'),foo: 'bar4'}}]},{schedule: [{booking: {reserved: false,foo: 'bar5'}}]}
        ]
    }
]

如果结构正确，则可以运行聚合

Clinic.aggregate(
    [
        {
            $project: {
                _id: 0,temp: '$dentists.schedule.booking'
            }
        },{
            $unwind: {
                path: '$temp'
            }
        },{
            $match: {
                'temp.reserved': true
            }
        },{
            $group: {
                _id: null,available_times: {
                    $addToSet: '$temp'
                }
            }
        }
    ]
)

您可以获得类似的结果

{
    _id: null,available_times: [
        {reserved: true,foo: "bar4"},{reserved: true,foo: "bar3"},foo: "bar1"}
    ]
}