如何从json输出中删除字段名称

如何解决如何从json输出中删除字段名称

在Laravel-5.8中，我通过控制器从数据库传递数据以使用JSON进行查看：

public function findNationalHoliday(Request $request)
{
   $nationalholidays               = HrNationalHoliday::select('holiday_date')->whereYear('created_at','=',date('Y'))->get();
 return response()->json([
    'nationalholidays' => $nationalholidays,]);        
}

然后将其发送到通过下面的ajax/json显示的视图：

< script type = "text/javascript" >
  var holidayDays = [];
$(document).ready(function() {
  $(document).on('change','#leave_type',function() {
    var air_id = $(this).val();

    var a = $(this).parent();

    var op = "";

    $.ajax({
      type: 'get',url: '{{ route('
      get.leavecounts.all ') }}',data: {
        'id': air_id
      },dataType: 'json',//return data will be json
      success: function(data) {
        holidayDays = data.nationalholidays;
        console.log(data.nationalholidays);
      },error: function() {

      }
    });
  });
}); <
/script>

0:
holiday_date: "2020-11-12 00:00:00"
__proto__: Object
1:
holiday_date: "2020-11-16 00:00:00"
__proto__: Object
2:
holiday_date: "2020-11-19 00:00:00"
__proto__: Object
3:
holiday_date: "2020-11-30 00:00:00"
__proto__: Object
4:
holiday_date: "2020-12-14 00:00:00"
__proto__: Object
5: {holiday_date: "2020-12-01 00:00:00"}
6: {holiday_date: "2020-12-10 00:00:00"}
length: 7
__proto__: Array(0)

如何删除字段名称holiday_date和时间00:00:00的尾随零？

但是只有日期。

谢谢

解决方法

您可以map收集集合以返回格式化值：

public function findNationalHoliday(Request $request) {
    $nationalholidays = HrNationalHoliday::select('holiday_date')
        ->whereYear('created_at','=',date('Y'))
        ->get()
        ->map(function ($nationalholiday) {
            return DateTime::createFromFormat('Y-m-d h:i:s',$nationalholiday->holiday_date)
                ->format('Y-m-d');
        });
    return response()->json([
        'nationalholidays' => $nationalholidays,]);
}