如何解决根据另一列中的初始字符串添加列值
我正在尝试根据另一列中是否存在特定字符值向列添加“是/否”字符值。
这是一个 example :
V2.x Clitic
1 can could NA
2 d should NA
如果^d中的第一列以^ll或example$V2.x开头，则example$Clitic中的值应为YES；如果不是，应该是NO。
所以在上面的 df 中，example[1,2] 应该是 NO，而 example[2,2] 应该是 YES。
希望在几百行和十几列的数据集上实现自动化。不知道该怎么做，尽管 grepl() 似乎很有用。非常感谢您的帮助。
结构：
structure(list(V2.x = structure(c(1L,19L),.Label = c("can could","can cud","can may","can might","can should","can will","can would","could can","could may","could might","could should","could used to","could will","d can","d could","d may","d might","d must","d should","d used to","d will","have to should","have to will","ll can","ll could","ll may","ll might","ll must","ll shall","ll should","ll used to","ll would","may can","may might","may must","may shall","may should","may used to","may will","may would","might can","might could","might may","might must","might shall","might should","might will","might would","might wud","must can","must will","must would","shall can","shall will","should can","should could","should may","should might","should must","should will","should would","used to could","will can","will could","will kin","will may","will might","will must","will shall","will should","will would","would can","would could","would may","would might","would must","would should","would will"),class = "factor"),Clitic = c(NA,NA)),row.names = 1:2,class = "data.frame")
解决方法
您已经在 let uri = new URL('https://example.com/path');
console.log(uri.toString());
// https://example.com/path/
中使用了返回逻辑值的正则表达式。
grepl要获得“是”/“否”值，请将其插入 grepl('^(d|ll)',example$V2.x)
#[1] FALSE TRUE
:
ifelse我们可以使用str_detect
library(stringr)
library(dplyr)
example %>%
mutate(Clitic = case_when(str_detect(V2.x,"^(d|ll)") ~ "Yes",TRUE ~ "No"))
版权声明：本文内容由互联网用户自发贡献，该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请发送邮件至 dio@foxmail.com 举报，一经查实，本站将立刻删除。