如何解决将 XML 解析为 Pandas Dataframe、Python 3.8、ElementTree
在 Python 3.8 中使用 ElementTree,如何将数据转换为 Pandas 数据框?
示例 XML:
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<SystemSourceSet id="-1" name="UC33brAvg_FM31" weight="0.5">
<!-- This model is an example and for review purposes only -->
<!-- Reference: UC33brAvg_FM31 -->
<!-- Description: UCERF 3.3 Branch Averaged Solution (FM31)-->
<Settings>
<DefaultMfds>
<IncrementalMfd floats="false" m="6.5" rate="0.0" type="SINGLE" weight="1.0"/>
</DefaultMfds>
</Settings>
<Source>
<IncrementalMfd m="6.449" rate="3.3631184e-05" type="SINGLE"/>
<Geometry depth="1.3" dip="50.0" indices="0:1" rake="-90.0" width="15.273"/>
</Source>
<Source>
<IncrementalMfd m="6.638" rate="1.5340160e-05" type="SINGLE"/>
<Geometry depth="1.3" dip="50.0" indices="0:2" rake="-90.0" width="15.273"/>
</Source>
<Source>
<IncrementalMfd m="6.78" rate="1.0903030e-05" type="SINGLE"/>
<Geometry depth="1.3" dip="50.0" indices="0:3" rake="-90.0" width="15.273"/>
</Source>
<Source>
<IncrementalMfd m="6.893" rate="7.3397665e-06" type="SINGLE"/>
<Geometry depth="1.3" dip="50.0" indices="0:4" rake="-90.0" width="15.273"/>
</Source>
预期数据帧:
解决方法
手动导航树并收集要保留的数据点:
from xml.etree import ElementTree
root = ElementTree.parse('data.xml').getroot()
data = []
for node in root:
if node.tag != 'Source':
continue
mfd = node.find('IncrementalMfd')
geometry = node.find('Geometry')
data.append({
'indices': geometry.get('indices'),'IncrementalMfd m': mfd.get('m'),'rate': mfd.get('rate'),'type': mfd.get('type'),'Geometry depth': geometry.get('depth'),'dip': geometry.get('dip'),'rake': geometry.get('rake'),'width': geometry.get('width')
})
df = pd.DataFrame(data)
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。