Oracle SQL - 日期来自/来自带有日期的表

如何解决Oracle SQL - 日期来自/来自带有日期的表

我有一个问题，我不知道如何解决它：

我有以下信息：

产品	IS_BUY	日期
A	1	01/01/2021
A	1	02/01/2021
A	1	03/01/2021
A	0	04/01/2021
A	1	05/01/2021
A	1	06/01/2021
B	1	01/01/2021
C	1	01/01/2021
C	0	02/01/2021
C	0	03/01/2021
C	1	04/01/2021

我需要在每个产品存在或不购买的日期之间留下以下结果：

产品	IS_BUY	FROM_DATE	TO_DATE
A	1	01/01/2021	04/01/2021
A	0	04/01/2021	05/01/2021
A	1	05/01/2021	null
B	1	01/01/2021	null
C	1	01/01/2021	02/01/2021
C	0	02/01/2021	04/01/2021
C	1	04/01/2021	null

感谢您的帮助！

解决方法

您没有告诉我们您的 Oracle 版本。下面我将展示两种解决方案：第一种是更高级的，使用 match_recognize 子句，在 Oracle 12.1 中添加，然后是较旧的方法，使用 Tabibitosan 方法解决间隙和岛屿问题（您的类问题属于）。

数据设置：

create table my_data (product,is_buy,eff_date) as
  select 'A',1,to_date('01/01/2021','mm/dd/yyyy') from dual union all
  select 'A',to_date('02/01/2021',to_date('03/01/2021',to_date('04/01/2021',to_date('05/01/2021',to_date('06/01/2021','mm/dd/yyyy') from dual union all
  select 'B','mm/dd/yyyy') from dual union all
  select 'C','mm/dd/yyyy') from dual
;

（顺便说一句，这是在帖子中包含示例数据的首选方式！）

注意 date 是保留关键字；我将列名称更改为 eff_date。

第一个解决方案，使用 match_recognize 匹配数据中的模式：

select product,eff_date,end_date
from   my_data
match_recognize(
  partition by product
  order     by eff_date
  measures  a.is_buy       as is_buy,a.eff_date     as eff_date,next(eff_date) as end_date
  pattern   ( a b* )
  define    b as is_buy = a.is_buy
);

PRODUCT IS_BUY EFF_DATE   END_DATE  
------- ------ ---------- ----------
A            1 01/01/2021 04/01/2021
A            0 04/01/2021 05/01/2021
A            1 05/01/2021           
B            1 01/01/2021           
C            1 01/01/2021 02/01/2021
C            0 02/01/2021 04/01/2021
C            1 04/01/2021           

第二种解决方案，仅使用解析函数和聚合（Tabibitosan 方法）：

with prep as (
  select product,lead(eff_date) over (partition by product 
                              order by eff_date) as next_date,row_number() over (partition by product         order by eff_date) -
         row_number() over (partition by product,is_buy order by eff_date)
                 as grp
  from   my_data
)
select product,min(eff_date) as eff_date,max(next_date) keep (dense_rank last order by eff_date) as end_date
from   prep
group  by product,grp
order  by product,eff_date
;

,

试试这个

Select
Product,Is_Buy,(select  min(x.DATE) from products x where x.product=a.product and x.is_buy=a.is_buy) from_date,(select  max(x.DATE) from products x where x.product=a.product and x.is_buy=a.is_buy) to_date,from products a
group by a.Product,a.Is_Buy