多级饼图散景

如何解决多级饼图散景

我目前正在尝试将散景中的饼图组合在一起,该饼图使用楔形字形代替预设饼图(需要更好的方法)。我想制作一个只有半个饼图的多级饼图,我发现我只需要乘以一个圆周率而不是两个圆周率即可。我还减去了我正在为下一级图层工作的相反角度以限制其范围,但是第二个角度到处都是,如果有人可以帮助我,请。先谢谢了。

attack1 = {'shots': ['home','away'],'shots':[144,48,36,128,27,41]}

attack2 = {'index':['shots','shots on target','goals'],'home':[144,36],'away':[128,41]}


attack1,attack2 = pd.DataFrame(attack1,index=['home','away']),pd.DataFrame(attack2,index=['shots','goals'])



c1 = YlGnBu

c2 = PuBu



attack1['colors'] = [c1[6][1],RdYlGn[6][3]]
attack1['angle'] = attack1['shots'] / attack1['shots'].sum() * pi # + 0.5*pi
attack1['pct'] = pct(attack1['shots'],attack1['shots'].sum())
attack1['pct'] = attack1['pct'].astype(str) + '%'
attack1['pct'] = attack1['pct'].str.pad(28,side='left')




attack2['colors'] = c2[6][2:5]
attack2['angle'] = attack2['home'] / attack2['home'].cumsum()  * (pi - attack1['angle'][0] -.255)          
attack2['pct'] = pct(attack2['home'],attack2['home'].sum())
attack2['pct'] = attack2['pct'].astype(str) + '%'

xP = 'home','away'
sourceAttack1 = ColumnDataSource(data=dict(x=xP,y=attack1['shots'],c=attack1['colors'],a=attack1['angle'],l=attack1['pct']))
sourceAttack2 = ColumnDataSource(data=dict(x=list(attack2.index.values),y=attack2['home'],c=attack2['colors'],a=attack2['angle'],l=attack2['pct']))



pA1 = figure(plot_height=450,plot_width=550,title='Attack',tools = 'pan,wheel_zoom,box_zoom,reset',x_range=(-0.4,0.9))

pA1.wedge(x=0,y=1,radius=0.4,start_angle=cumsum('a',include_zero=True),end_angle=cumsum('a'),line_color='white',fill_color='c',legend_field='x',source=sourceAttack1)

pA1.wedge(x=0,radius=0.3,source=sourceAttack2)

hA1 = HoverTool()
hA1.tooltips=[('location','@x'),('shots','@y'),('pct','@l')]

lA1 = LabelSet(x=0,text='l',text_color='black',text_font_size='15px',text_align='left',angle=cumsum('a',source=sourceAttack1,render_mode='canvas') # y_offset=50


pA1.add_tools(hA1)
pA1.axis.axis_label=None
pA1.axis.visible=False
pA1.grid.grid_line_color = None
pA1.legend.background_fill_alpha=None
pA1.legend.border_line_alpha=0
pA1.legend.location= (0,50) #'center_right'
pA1.legend.label_text_font_size = "15px"
pA1.legend.orientation ='vertical'
pA1.title.text_font_size = '25px'
pA1.toolbar.autohide = True
pA1.outline_line_color=None



show(pA1)

这是目前的结果

halfPie

解决方法

事实证明,在为我正在寻找的东西创建一个最小的示例时,我最终按照我的意愿制作了它。谢谢@mosc9575,也许我只需要离开一会儿。

#values
attack = [200,80,34,190,85,40,314,315 ]
overall = {'attack': attack}
index = ['shots','shotsT','goals','shotsA','shotsTA','goalsA','attackHome','attackAway']

#dataframe
dfpie = pd.DataFrame(overall,index = index)
dfpie['color'] = viridis(len(dfpie.index))

#df without overal which would be the first pie chart
dfpie1 = dfpie.iloc[:-2]

#df overall
dfpie2 = pd.DataFrame(dfpie.iloc[-2:])


#angle for both df * pi instead *2*pi to keep it half circumference C=2πr
dfpie1['angles'] = dfpie1['attack'] / dfpie1['attack'].sum() * pi
dfpie2['angles'] = dfpie2['attack'] / dfpie2['attack'].sum() * pi

#sources
sa1 = ColumnDataSource(data=dict(x=list(dfpie2.index.values),y=dfpie2['attack'],c=dfpie2['color'],a=dfpie2['angles']))
sa2 = ColumnDataSource(data=dict(x=list(dfpie1.index.values),y=dfpie1['attack'],c=dfpie1['color'],a=dfpie1['angles']))

#figure instance
piA = figure(plot_height=450,plot_width=550,title='Attack',tools = 'pan,wheel_zoom,box_zoom,reset',x_range=(-0.4,0.9))

#glyph
piA.wedge(x=0,y=1,radius=0.4,start_angle=cumsum('a',include_zero=True),end_angle=cumsum('a'),line_color='white',fill_color='c',legend_field='x',source=sa1)

#overlay glyph
piA.wedge(x=0,radius=0.3,source=sa2)


#remove grid lines
piA.axis.axis_label=None
piA.axis.visible=False
piA.grid.grid_line_color = None
piA.outline_line_color=None


show(piA)

result

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