PHP 从预填充的下拉菜单中插入表单数据

如何解决PHP 从预填充的下拉菜单中插入表单数据

我有一个表单，用户可以在其中填写输入框和下拉菜单。我有两个菜单：教师和部门，这些选择是从数据库中预先填充的，供用户选择。我用于带有手动添加的“选择”选项的框的代码工作正常，但不适用于预填充的框。

//Code to populate the faculty dropdown. 
$result = $wpdb->get_results ( "SELECT fName,lName FROM Faculty order by lName" );
Faculty Member (If Applicable)
<select>
  <option selected="selected">- Select -</option>
  <?php
  foreach( $result as $value )
  { ?>
    <option value="<?php echo $value->fName; ?>"><?php echo $value->fName.' '.$value->lName; ?> 
 </option>
  }
</select>

//How I'm saving the other inputs,department and faculty will not work using this. 
$activity = $_POST['activity_Name'];
     $cont_Name = $_POST['cont_Name'];
     $cont_phone = $_POST['cont_phone'];
     $cont_email = $_POST['cont_email'];
     $faculty_ID = 30;  //hard-coded for now b/c dropdown box selection not working 
     $course_ID = $_POST['course_ID'];
     //$category_ID = $category previously defined above 
     //$age_ID = $age previously defined above
     $dept_ID = 1;  //same for this one 
     $Start_Date = $_POST['start_date'];
     $End_Date = $_POST['end_date'];
     $location = $_POST['Location'];
     $URL = $_POST['URL'];
     
     
     $wpdb->insert('Activity',array('activity_ID' => 'null','activity_Name' => $activity,'cont_Name' => $cont_Name,'cont_phone' => $cont_phone,'cont_email' => $cont_email,'faculty_ID' => $faculty_ID,'course_ID' => $course_ID,'category_ID' => $category,'age_ID' => $age,'dept_ID' => $dept_ID,'Start_Date' => $Start_Date,'End_Date' => $End_Date,'Location' => $location,'URL' => $URL));
     
 //Activity Title
 echo("Activity Title: " . $activity . "<br />\n");
 
 //Contact Name 
 echo("Contact Name: " . $cont_Name . "<br />\n");
 
 //Contact Email
 echo("Contact Email: " . $cont_email . "<br />\n");
 
 //Contact Phone 
 echo("Contact Phone: " . $cont_phone . "<br />\n");
 

解决方法

<select>

首先，您的 select 没有名称，因此 select 中的任何值都不会随表单一起发送。

<option value="<?php echo $value->fName; ?>"><?php echo $value->fName.' '.$value->lName; ?> 

并且您将 fName 分配给选项值，但您需要的是教师 ID。我认为您想将教员 ID 分配给选项值。

<option value="<?php echo $value->faculty_ID; ?>"><?php echo $value->fName.' '.$value->lName; ?>