如何解决我在双向链表中的交换代码有问题
我用 C 编写了交换代码 但我在学校编译器中没有得到完美的成绩。 我认为以下代码有问题。 我用结构体和指针制作了双向链表。 节点定义为:
struct node* newnode(char x)
{
struct node* new = (struct node*)malloc(sizeof(struct node));
new->next = NULL;
new->prev = NULL;
new->c = x;
return new;
}
下面的代码是交换代码,我让每个函数因子表示“struct node*p”是从头到尾的完整列表,“int a and b”是列表的等级 “count1(p)”是计算完整列表中的节点并返回节点数(不包括头和尾)的函数。
void swap(struct node* p,int a,int b)
{
int x,y;
struct node* x1,* x2,emp = { 0 };
int i = 0;
x1 = p;
x2 = p;
if (a >= b) {
x = b;
y = a;
}
else {
x = a;
y = b;
}
if (b <= 0 || a <= 0 || a > N || a > count1(p) || b > N || b > count1(p)) {
printf("invalid position\n");
return;
}while (i < x && x1 != tail) {
x1 = x1->next;
i++;
}
i = 0;
while (i < y && p != tail) {
x2 = x2->next;
i++;
}
if (x1->next != x2)
{
x1->prev->next = x2;
x1->next->prev = x2;
x2->prev->next = x1;
x2->next->prev = x1;
emp.next = x1->next;
emp.prev = x1->prev;
x1->next = x2->next;
x1->prev = x2->prev;
x2->next = emp.next;
x2->prev = emp.prev;
}
if (x1->next == x2)
{
emp.prev = x1->prev;
emp.next = x1->next;
x1->prev->next = x2;
x2->next->prev = x1;
x1->prev = x2;
x1->next = x2->next;
x2->prev = emp.prev;
x2->next = x1;
}
}
以下代码是我的完整代码:
#include<stdio.h>
#include<stdlib.h>
int N;
struct node {
struct node* next;
struct node* prev;
char c;
};
struct node* head,* tail;
void reset() {
head = (struct node*)malloc(sizeof(struct node));
tail = (struct node*)malloc(sizeof(struct node));
head->prev = NULL;
head->next = tail;
head->c = NULL;
tail->prev = head;
tail->next = NULL;
tail->c = NULL;
}
struct node* newnode(char x)
{
struct node* new = (struct node*)malloc(sizeof(struct node));
new->next = NULL;
new->prev = NULL;
new->c = x;
return new;
}
void prcount(struct node* p)
{
printf("%d\n",count1(p));
}
int count1(struct node* p)
{
int sum = 0;
while (p != tail) {
p = p->next;
sum++;
}
return sum + -1;
}
void add1(struct node* p,int n,char x)
{
struct node* new1 = newnode(x);
int i = 1;
if (n <= 0 || n > N || n > count1(p) + 1) {
printf("invalid position\n");
return;
}
while (i < n && p != tail) {
p = p->next;
i++;
}
p->next->prev = new1;
new1->prev = p;
new1->next = p->next;
p->next = new1;
}
void delete1(struct node* p,int n)
{
int i = 0;
if (n <= 0 || n > N || n > count1(p)) {
printf("invalid position\n");
return;
}
while (i < n && p != tail)
{
p = p->next;
i++;
}
p->prev->next = p->next;
p->next->prev = p->prev;
free(p);
}
void get1(struct node* p,int n) {
int i = 0;
if (n <= 0 || n > N || n > count1(p)) {
printf("invalid position\n");
return;
}while (i < n && p != tail) {
p = p->next;
i++;
}
printf("%c\n",p->c);
}
void print1(struct node* p)
{
int i = 0;
if (count1(p) == 0) {
printf("invalid position\n");
return;
}
while (i < N && p->next != tail)
{
p = p->next;
printf("%c",p->c);
i++;
}
printf("\n");
}void removeall(struct node* p)
{
struct node* emp;
p = p->next;
while (p != tail)
{
emp = p->next;
free(p);
p = emp;
}
head->prev = NULL;
head->next = tail;
head->c = NULL;
tail->prev = head;
tail->next = NULL;
tail->c = NULL;
}
void swap(struct node* p,y;
struct node* x1,emp = { 0 };
int i = 0;
x1 = p;
x2 = p;
if (a >= b) {
x = b;
y = a;
}
else {
x = a;
y = b;
}
if (b <= 0 || a <= 0 || a > N || a > count1(p) || b > N || b > count1(p)) {
printf("invalid position\n");
return;
}while (i < x && x1 != tail) {
x1 = x1->next;
i++;
}
i = 0;
while (i < y && x2 != tail) {
x2 = x2->next;
i++;
}
if (x1->next != x2)
{
x1->prev->next = x2;
x1->next->prev = x2;
x2->prev->next = x1;
x2->next->prev = x1;
emp.next = x1->next;
emp.prev = x1->prev;
x1->next = x2->next;
x1->prev = x2->prev;
x2->next = emp.next;
x2->prev = emp.prev;
}
if (x1->next == x2)
{
emp.prev = x1->prev;
emp.next = x1->next;
x1->prev->next = x2;
x2->next->prev = x1;
x1->prev = x2;
x1->next = x2->next;
x2->prev = emp.prev;
x2->next = x1;
}
}
int main()
{
int i;
int r,n;
char x,y;
reset();
scanf("%d",&N);
for (i = 0; i < N; i++)
{
scanf(" %c",&x);
if (x == 'A') {//A mean add(head,char x) -> add 'x' on a rank in list
scanf("%d",&r);
scanf(" %c",&y);
add1(head,r,y);
}
else if (x == 'D') {// D mean delete(struct node *head,int a) -> delete element on int a rank
scanf("%d",&r);
delete1(head,r);
}
else if (x == 'G') {//G mean Get(head,int a)-> print element on int a rank
scanf("%d",&r);
get1(head,r);
}
else if (x == 'P') {//P mean print(head) -> print all element in list
print1(head);
}
else if (x == 'R') {//R mean Removeall(head) -> remove all node (exclude head and tail0
removeall(head);
}
else if (x == 'C')//C Mean prcount(head) -> count and print number of node in list (exclude head and tail)
{
prcount(head);
}
else if (x == 'S') {//S mean Swap(head,int b) -> swap element of int a rank with int b rank
scanf("%d",&r);
scanf("%d",&n);
swap(head,n);
}
}
removeall(head);
}
这是我的完整代码。 我想知道有什么问题或者更有效的方法来制作交换码?
解决方法
#include<stdio.h>
#include<stdlib.h>
int N;
struct node {
struct node* next;
struct node* prev;
char c;
};
struct node* head,* tail;
void reset() {
head = (struct node*)malloc(sizeof(struct node));
tail = (struct node*)malloc(sizeof(struct node));
head->prev = NULL;
head->next = tail;
head->c = NULL;
tail->prev = head;
tail->next = NULL;
tail->c = NULL;
}
struct node* newnode(char x)
{
struct node* new = (struct node*)malloc(sizeof(struct node));
new->next = NULL;
new->prev = NULL;
new->c = x;
return new;
}
void prcount(struct node* p)
{
printf("%d\n",count1(p));
}
int count1(struct node* p)
{
int sum = 0;
while (p != tail) {
p = p->next;
sum++;
}
return sum + -1;
}
void add1(struct node* p,int n,char x)
{
struct node * new1 = newnode(x);
int i = 1;
if (n<=0||n > N || n > count1(p) + 1) {
printf("invalid position\n");
return;
}
while (i < n && p != tail) {
p = p->next;
i++;
}
p->next->prev = new1;
new1->prev = p;
new1->next = p->next;
p->next = new1;
}
void delete1(struct node* p,int n)
{
int i = 0;
if (n <= 0 || n > N || n > count1(p)) {
printf("invalid position\n");
return;
}
while (i < n && p != tail)
{
p = p->next;
i++;
}
p->prev->next = p->next;
p->next->prev = p->prev;
free(p);
}
void get1(struct node* p,int n) {
int i = 0;
if (n <= 0 || n > N || n > count1(p)) {
printf("invalid position\n");
return;
}while (i < n && p != tail) {
p = p->next;
i++;
}
printf("%c\n",p->c);
}
void print1(struct node* p)
{
int i = 0;
if (count1(p) == 0) {
printf("invalid position\n");
return;
}
while (i < N && p->next != tail)
{
p = p->next;
printf("%c",p->c);
i++;
}
printf("\n");
}void removeall(struct node* p)
{
struct node* emp;
p = p->next;
while (p != tail)
{
emp = p->next;
free(p);
p = emp;
}
head->prev = NULL;
head->next = tail;
head->c = NULL;
tail->prev = head;
tail->next = NULL;
tail->c = NULL;
}
void swap(struct node* p,int a,int b)
{
int x,y;
struct node* x1,* x2,emp = { 0 };
int i = 0;
x1 = p;
x2 = p;
if (a >= b) {
x = b;
y = a;
}
else {
x = a;
y = b;
}
if (b <= 0 || a <= 0 || a > N || a > count1(p) || b > N || b > count1(p)) {
printf("invalid position\n");
return;
}while (i < x && x1 != tail) {
x1 = x1->next;
i++;
}
i = 0;
while (i < y && p != tail) {
x2 = x2->next;
i++;
}
if (x1->next != x2)
{
x1->prev->next = x2;
x1->next->prev = x2;
x2->prev->next = x1;
x2->next->prev = x1;
emp.next = x1->next;
emp.prev = x1->prev;
x1->next = x2->next;
x1->prev = x2->prev;
x2->next = emp.next;
x2->prev = emp.prev;
}
if (x1->next == x2)
{
emp.prev = x1->prev;
emp.next = x1->next;
x1->prev->next = x2;
x2->next->prev = x1;
x1->prev = x2;
x1->next = x2->next;
x2->prev = emp.prev;
x2->next = x1;
}
}
int main()
{
int i;
int r,n;
char x,y;
reset();
scanf("%d",&N);
for (i = 0; i < N; i++)
{
scanf(" %c",&x);
if (x == 'A') {
scanf("%d",&r);
scanf(" %c",&y);
add1(head,r,y);
}
else if (x == 'D') {
scanf("%d",&r);
delete1(head,r);
}
else if (x == 'G') {
scanf("%d",&r);
get1(head,r);
}
else if (x == 'P') {
print1(head);
}
else if (x == 'R') {
removeall(head);
}
else if (x == 'C')
{
prcount(head);
}
else if (x == 'S') {
scanf("%d",&r);
scanf("%d",&n);
swap(head,n);
}
}
removeall(head);
}
这是我的完整代码
,int N
用作 main
中输入命令的数量。在您的列表函数中与 N
进行比较(好像 N
表示节点数)没有意义 - 您可以删除它们。
Besides that,there are some places where a compiler with appropriate options would issue warnings - perhaps that's why you didnt get perfect grade in school compiler.
head->c = NULL;
由于 c
是 char
类型并且 NULL
是一个 空指针常量,所以这不合适;改为
head->c = '\0'; // or head->c = 0;
printf("%d\n",count1(p));
在声明之前调用 count1
。使用前声明它
int count1(struct node* p);
或将函数定义移动到第一个使用它的函数之前。
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