类型 uuid 的无效输入语法:PosgreSQL 复制命令中的“”或“null”

如何解决类型 uuid 的无效输入语法:PosgreSQL 复制命令中的“”或“null”

我已经从 SELECT 查询创建了 csv-backup,现在尝试将它导入回数据库。但我收到此错误:

COPY doc FROM '/tmp/doc.csv' DELIMITER ',' CSV HEADER;


ERROR: invalid input syntax for type uuid: "null"

如您所见,我的文件中的 "null" 为 NULL。

这发生在之前为空的可选字段上。

我找到了这个解决方案:https://stackoverflow.com/a/40428667/8443131

但它对我不起作用:

COPY doc FROM '/tmp/doc.csv' DELIMITER ',' CSV HEADER QUOTE '"null"' NULL '';

ERROR:  COPY quote must be a single one-byte character

我如何导入这个文件?

UPD:我尝试用空引号替换空值。

尝试过的命令:

COPY doc FROM '/tmp/null.csv' DELIMITER ',' CSV HEADER QUOTE '"' NULL '';

ERROR:  invalid input syntax for type uuid: ""

文件的简短版本:

"id","removed","modified_at","root_id","parent_id","acl","properties","data","file_meta"
"f6a16ff7-4a31-11eb-be7b-8344edc8f36b","false","2021-01-04 00:00:12.347988","","IS_PUBLIC",""
"2fdd0b8b-4a70-11eb-99fd-ad786a821574","2021-01-04 00:00:06.87298",""
"2c6d5fd1-4a70-11eb-99fd-ad786a821574","2021-01-04 00:00:07.536212",""
"fd645c21-4a6f-11eb-99fd-ad786a821574","2021-01-04 00:00:11.892367",""
"35c1fc53-4a70-11eb-99fd-ad786a821574","2021-01-04 00:00:05.517109",""
"35d165a4-4a70-11eb-99fd-ad786a821574","2021-01-04 00:00:01.72546",""
"fd40806d-4a6f-11eb-99fd-ad786a821574","2021-01-04 00:00:09.173726",""
"30ba4b45-4a70-11eb-99fd-ad786a821574","2021-01-04 00:00:04.655073",""

表创建:


-- Dumped from database version 13.0 (Debian 13.0-1.pgdg100+1)
-- Dumped by pg_dump version 13.0 (Debian 13.0-1.pgdg100+1)



CREATE TABLE public.doc (
    id uuid NOT NULL,removed boolean,modified_at timestamp without time zone,root_id uuid,parent_id uuid,acl jsonb,properties jsonb,data jsonb,file_meta jsonb
);



ALTER TABLE ONLY public.doc
    ADD CONSTRAINT doc_pkey PRIMARY KEY (id);

ALTER TABLE ONLY public.doc
    ADD CONSTRAINT fk_document_entity FOREIGN KEY (id) REFERENCES public.main_table(id);

ALTER TABLE ONLY public.doc
    ADD CONSTRAINT fk_document_parent FOREIGN KEY (parent_id) REFERENCES public.doc(id);

解决方法

我使用以下内容复制了您的案例,假设第二列是 boolean,第三列是 timestamp

create table test (col1 varchar,col2 boolean,col3 timestamp,col4 varchar,col5 varchar,col6 varchar,col7 varchar,col8 varchar,col9 varchar)                                  ;                                                                                               

如果我现在使用

copy test from STDIN delimiter ',' CSV QUOTE '"' NULL 'null';

并传递您提到的字符串

"f6a16ff7-4a31-11eb-be7b-8344edc8f36b","false","2021-01-04 00:00:12.347988","null","IS_PUBLIC","null"

数据解析正确

COPY 1

表格的输出看起来是正确的。

defaultdb=> select * from test;
                 col1                 | col2 |            col3            | col4 | col5 |   col6    | col7 | col8 | col9 
--------------------------------------+------+----------------------------+------+------+-----------+------+------+------
 f6a16ff7-4a31-11eb-be7b-8344edc8f36b | f    | 2021-01-04 00:00:12.347988 | null | null | IS_PUBLIC | null | null | null
(1 row)
,

您无法使用 COPY 加载此文件,因为 "null" 用双引号引起来,因此不能用作 NULL 占位符 - 它始终被解释为字符串。

您能做的最好的事情是将文件加载到一个表中,其中相应的列定义为 text,然后执行类似的操作

ALTER TABLE doc ALTER uuidcol TYPE uuid USING CAST(nullif(uuidcol,'null') AS uuid);
,

即使@Abelisto 命令正在工作,我仍然无法上传一些 jsonb 行。

但我也有一个 .json 替代我的文件,如下所示:

[
    {
        "c0": "f6a16ff7-4a31-11eb-be7b-8344edc8f36b","c1": false,"c2": "2021-01-04 00:00:12.347988","c3": null,"c4": null,"c5": "IS_PUBLIC","c6": null,"c7": null,"c8": null
    },...
]

所以我最终编写了这个对我有用的python脚本:

import json
import psycopg2
from datetime import datetime
import uuid


connection = psycopg2.connect(user="admin",password="admin",host="127.0.0.1",port="5432",database="postgres")
cursor = connection.cursor()


def insertLine(line):

    id = uuid.UUID(line['c0']).hex

    removed = bool(line['c1'])

    modified_at = datetime.strptime(line['c2'],'%Y-%m-%d %H:%M:%S.%f')

    root_id = uuid.UUID(line['c3']).hex if line['c3'] else None
    parent_id = uuid.UUID(line['c4']).hex if line['c4'] else None

    acl = json.dumps(line['c5']) if line['c5'] else None

    properties = json.dumps(line['c6']) if line['c6'] else None
    data = json.dumps(line['c7']) if line['c7'] else None
    file_meta = json.dumps(line['c8']) if line['c8'] else None

    record_to_insert = (id,removed,modified_at,root_id,parent_id,acl,properties,data,file_meta)

    try:
        postgres_insert_query = """INSERT INTO doc (id,file_meta) VALUES (%s,%s,%s)"""
        
        cursor.execute(postgres_insert_query,record_to_insert)

        connection.commit()
        count = cursor.rowcount


    except psycopg2.Error as error:
        print("ERROR:" + str(error))


file = 'table.json'

with open(file) as json_file:
    data = json.load(json_file)
    for p in data:
        insertLine(p)


if connection:
    cursor.close()
    connection.close()
    print("PostgreSQL connection is closed")

所以我想在 csv 中备份 jsonb 字段是不好的做法。

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