在一个函数中运行不同长度的数组

如何解决在一个函数中运行不同长度的数组

我想在我的 Arduino 上制作一个蜂鸣器，一个接一个地播放不同的歌曲。我已经把音符放在数组中来组成歌曲和一个函数来调用不同的数组。我的问题是数组的长度不同，这会导致我播放它们时歌曲被剪切。我已经在“int arrSize”中定义了长度，并将其设置为名为 MikkelRev_melody 的数组的长度，但是较长的歌曲会被剪切掉。有没有人知道解决这个问题的好方法？

这是我的代码：

int buzzer = 13;
int tempo = 120; //melodiens tempo i bpm

//Defining the needed notes 
#define T_C 262
#define T_D 294
#define T_E 330
#define T_F 349
#define T_G 392
#define T_A 440
#define T_Ab 466
#define T_B 493
#define T_C2 523
#define T_D2 587

//arrays with notes
int AlleFugler_melody[] = {T_C,T_E,T_G,T_C2,T_A,T_F,T_C,T_D,T_C};

int MikkelRev_melody[] = {T_E,T_G};

int LisaGikkTilSkolen_melody[] = {T_C,T_C};

int LilleMaltrost_melody[] = {T_E,T_D};

int BjornenSover_melody[] = {T_C,T_C};

int BamsesFodselsdag_melody[] = {T_C2,T_D2,T_Ab,T_F};

//duration of each note
int AlleFugler_durations[] = {2,4,6,2,2};

int MikkelRev_durations[] = {4,2};

int LisaGikkTilSkolen_durations[] = {4,2};

int LilleMaltrost_durations[] = {6,2};

int BjornenSover_durations[] = {4,2};

int BamsesFodselsdag_durations[] = {4,2};


void setup() 
{
  pinMode(13,OUTPUT);
  PlaySong(LisaGikkTilSkolen_melody,LisaGikkTilSkolen_durations,tempo);
  PlaySong(MikkelRev_melody,MikkelRev_durations,tempo);
  PlaySong(AlleFugler_melody,AlleFugler_durations,tempo);
  PlaySong(LilleMaltrost_melody,LilleMaltrost_durations,tempo);
  PlaySong(BjornenSover_melody,BjornenSover_durations,tempo);
  PlaySong(BamsesFodselsdag_melody,BamsesFodselsdag_durations,tempo);
}

void loop() 
{
}

void PlaySong(int notes[],int durations[],int BPM)
{ 
  int arrSize = sizeof(MikkelRev_melody)/sizeof(int); //leanght of array playing
  
  for (int thisNote = 0; thisNote < arrSize; thisNote++) 
  {
    int noteDuration = (int)((750 * (120 * 2 / BPM)) / durations[thisNote] + 0.); //defining duration of tone
    tone(buzzer,notes[thisNote],noteDuration);

    int pauseBetweenNotes = noteDuration * 1.20; //defining pause between tones
    delay(pauseBetweenNotes); //leanght of tone
    noTone(buzzer); //add pause between tones 
  }
  delay(1000); //one second pause before next song
}

解决方法

有多种方式。我会像 C 字符串那样做。再定义一个值为 0 或 -1 的音符并将其放在每个数组的末尾。然后迭代数组，直到达到该值。