如何解决检查给定的 IP 是否在给定的网络范围内或不在 C 中
我在一次面试中被问到这个问题,我被严格要求使用 C/C++ 进行编程。我不太喜欢 C++,我试过用 C 编写代码,谁能帮我改进我的代码,它工作得很好,但我认为这不是最好的解决方法。
问题:检查给定的 IP 是否在网络范围内或不使用 C。例如:IP 地址:192.168.0.1 和网络:192.168.0.0/24 => 答案应该是,它在网络范围内。
我的回答如下,但我们可以改进吗? 谁能分享他们对这个问题的答案?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char *int_to_bin(unsigned short n){
char *result = malloc(n);
int c,k;
char ch = '1';
char ch1 = '0';
for (c=7; c>=0; c--){
k = n >> c; //Convert Integer to Binary by Right Shift Operation
if(k & 1){
strncat(result,&ch,1);
}
else{
strncat(result,&ch1,1);
}
}
return result;
}
int main(){
unsigned short n1,n2,n3,n4;
unsigned short m1,m2,m3,m4,m5;
char ip[33];
char sub[49];
printf("Enter an IP address\n");
scanf("%s",ip);
sscanf(ip,"%hu.%hu.%hu.%hu",&n1,&n2,&n3,&n4);
printf("Enter a Subnet address\n");
scanf("%s",sub);
sscanf(sub,"%hu.%hu.%hu.%hu/%hu",&m1,&m2,&m3,&m4,&m5);
char target[ 33 ]; //This variable will store the 1s and 0s after converting IP address into binary
char target1[ 49 ]; //This variable will store the 1s and 0s after converting Subnet address into binary
char *a = int_to_bin(n1);
char *b = int_to_bin(n2);
char *c = int_to_bin(n3);
char *d = int_to_bin(n4);
char *o = int_to_bin(m1);
char *p = int_to_bin(m2);
char *q = int_to_bin(m3);
char *r = int_to_bin(m4);
strcat(target,a);
strcat(target,b);
strcat(target,c);
strcat(target,d);
strcat(target1,o);
strcat(target1,p);
strcat(target1,q);
strcat(target1,r);
//printf("%s\n",target);
//printf("%s\n",target1);
int i;
for (i=0; i<m5; i++){
if(target[i] != target1[i]){
printf("IP is not in Subnet range\n");
exit(0);
}
}
printf("IP is in Subnet range\n");
return 0;
}
解决方法
我做了一些更改,我的代码如下所示。如果您认为其中有任何错误,请告诉我:
- 我正在接受输入并使用 sscanf 函数,将每个八位字节存储为整数格式。
- 然后使用int_to_bin函数,使用右移操作将整数转换为二进制并存储到字符数组中。
- 然后我在最后做 strcat 以组合数组。
- 最后,我使用 'for' 循环进行前缀匹配。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char *int_to_bin(unsigned short n){
char *result;
int c,d,t;
t=0;
result = (char*)malloc(32+1);
if (result == NULL)
exit(EXIT_FAILURE);
for (c=7; c>=0; c--){
d = n >> c; //Convert Integer to Binary by Right Shift Operation
if(d & 1){
*(result+t) = 1 + '0';
}
else{
*(result+t) = 0 + '0';
}
t++;
}
*(result+t) = '\0';
return result;
}
int main(){
unsigned short n1,n2,n3,n4;
unsigned short m1,m2,m3,m4,m5;
char ip[33];
char sub[49];
printf("Enter an IP address\n");
scanf("%s",ip);
sscanf(ip,"%hu.%hu.%hu.%hu",&n1,&n2,&n3,&n4); //This will store each octet in integer format
printf("Enter a Network address\n");
scanf("%s",sub);
sscanf(sub,"%hu.%hu.%hu.%hu/%hu",&m1,&m2,&m3,&m4,&m5); //This will store each octet in integer format
char target[ 33 ]; //This variable will store the 1s and 0s after converting IP address into binary
char target1[ 49 ]; //This variable will store the 1s and 0s after converting Subnet address into binary
char *a = int_to_bin(n1);
char *b = int_to_bin(n2);
char *c = int_to_bin(n3);
char *d = int_to_bin(n4);
char *o = int_to_bin(m1);
char *p = int_to_bin(m2);
char *q = int_to_bin(m3);
char *r = int_to_bin(m4);
strcat(target,a);
strcat(target,b);
strcat(target,c);
strcat(target,d);
strcat(target1,o);
strcat(target1,p);
strcat(target1,q);
strcat(target1,r);
//printf("%s\n",target);
//printf("%s\n",target1);
int i;
for (i=0; i<m5; i++){
if(target[i] != target1[i]){
printf("IP is not in given Network range\n");
exit(0);
}
}
printf("IP is in given Network range\n");
return 0;
}
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。