回调方法并执行while循环

如何解决回调方法并执行while循环

我是一个初学者/学生，在一些基本概念上苦苦挣扎。一世 我正在尝试回调我的 displaymenu 方法，以便当用户 输入正确的字符，它会提示他们输入温度 ints 然后完成后，让他们再次选择温度 直到他们选择退出选项。

这是我目前的代码：

import java.util.Locale;
import java.util.Scanner;

public class project7 {
    static Scanner kb = new Scanner(System.in);

    public static int fartocel(int f){


        f = ( f - 32 ) * 5 / 9;
        return f;
    }
    public static int caltofar(int c){

        c = c * 9 / 5 + 32;
        return c;
    }
public static char displaymenu(){
    char pick;
    boolean first;

    first = false;
    do {

        System.out.println("\nF - Far ");
        System.out.println("C - Cel ");
        System.out.println("Q - quit");
        System.out.print("\nPick: ");
        pick = Character.toUpperCase(kb.next().charAt(0));

        switch (pick) {
            case 'C':
            case 'F':
            case 'Q':
                first = true;
                break;
            default:
                System.out.println("\nPlease choose F,C,or Q");
                break;
        }
    }while (!first);

    return pick;

}

    public static void main(String[] args)  {
int c;
int f;
String answer;






    System.out.println("\n\nYou picked: " + displaymenu());

do {

    System.out.print("Enter the Cel temp: ");
    c = kb.nextInt();
    System.out.println("The temp " + c + " Cel " + "is Far " + caltofar(c));


    System.out.print("enter the Far temp: ");
    f = kb.nextInt();
    System.out.print("The temp " + f + "Far " + "is Cel " + fartocel(f));
    System.out.println("\n\nTry again?  Yes or No ");
answer = kb.next();
}
while (answer.equalsIgnoreCase("Yes"));



    }

}

解决方法

我正在尝试回调我的显示菜单方法

此处不建议使用短语回调，因为它可能会导致与 callback 函数混淆；只需说再打电话。为此，请更改

    System.out.println("\n\nYou picked: " + displaymenu());

do {
    …
    System.out.println("\n\nTry again?  Yes or No ");
answer = kb.next();
}
while (answer.equalsIgnoreCase("Yes"));

到

    for (char picked; (picked = displaymenu()) != 'Q'; )
    {
    …
    }