Outlook 日历导出类型问题

如何解决Outlook 日历导出类型问题

我有以下代码用于提取我的 Outlook 日历并向我显示我安排的会议中所有参与者的列表。我遇到了以下与数据类型相关的错误。我相信问题实际上是让事件被拉取，因为当我在错误之前打印约会列表时，它显示为空白。想法？

代码：

import datetime as dt
import pandas as pd
import win32com.client

def get_calendar(begin,end):
    outlook = win32com.client.Dispatch('Outlook.Application').GetNamespace('MAPI')
    calendar = outlook.getDefaultFolder(9).Items
    calendar.IncludeRecurrences = True
    calendar.Sort('[Start]')
    restriction = "[Start] >= '" + begin.strftime('%m/%d/%Y') + "' AND [END] <= '" + end.strftime('%m/%d/%Y') + "'"
    calendar = calendar.Restrict(restriction)
    return calendar

def get_appointments(calendar,subject_kw = None,exclude_subject_kw = None,body_kw = None):
    if subject_kw == None:
        appointments = [app for app in calendar]    
    else:
        appointments = [app for app in calendar if subject_kw in app.subject]
    if exclude_subject_kw != None:
        appointments = [app for app in appointments if exclude_subject_kw not in app.subject]
    cal_subject = [app.subject for app in appointments]
    cal_start = [app.start for app in appointments]
    cal_end = [app.end for app in appointments]
    cal_body = [app.body for app in appointments]

    df = pd.DataFrame({'subject': cal_subject,'start': cal_start,'end': cal_end,'body': cal_body})
    return df

def make_cpd(appointments):
    appointments['Date'] = appointments['start']
    appointments['Hours'] = (appointments['end'] - appointments['start']).dt.seconds/3600
    appointments.rename(columns={'subject':'Meeting Description'},inplace = True)
    appointments.drop(['start','end'],axis = 1,inplace = True)
    summary = appointments.groupby('Meeting Description')['Hours'].sum()
    return summary

final = r"C:\Users\rcarmody\Desktop\Python\Accelerators\Outlook Output.xlsx" 

begin = dt.datetime(2021,1,1)
end = dt.datetime(2021,5,12)

print(begin)
print(end)

cal = get_calendar(begin,end)
appointments = get_appointments(cal,subject_kw = 'weekly',exclude_subject_kw = 'Webcast')
result = make_cpd(appointments)

result.to_excel(final)

错误：

Traceback (most recent call last):
  File "C:\Users\Desktop\Python\Accelerators\outlook_meetings.py",line 50,in <module>
    result = make_cpd(appointments)
  File "C:\Users\Desktop\Python\Accelerators\outlook_meetings.py",line 34,in make_cpd
    appointments['Hours'] = (appointments['end'] - appointments['start']).dt.seconds/3600
  File "C:\Users\AppData\Roaming\Python\Python39\site-packages\pandas\core\generic.py",line 5461,in __getattr__
    return object.__getattribute__(self,name)
  File "C:\Users\rcarmody\AppData\Roaming\Python\Python39\site-packages\pandas\core\accessor.py",line 180,in __get__
    accessor_obj = self._accessor(obj)
  File "C:\Users\AppData\Roaming\Python\Python39\site-packages\pandas\core\indexes\accessors.py",line 494,in __new__
    raise AttributeError("Can only use .dt accessor with datetimelike values")
AttributeError: Can only use .dt accessor with datetimelike values
[Finished in 1.2s]

新错误：

Traceback (most recent call last):
  File "C:\Users\Desktop\Python\Accelerators\outlook_meetings.py",in make_cpd
    appointments['Hours'] = (appointments['end'] - appointments['start']) / pd.Timedelta(hours=1)
  File "C:\Users\\AppData\Roaming\Python\Python39\site-packages\pandas\core\ops\common.py",line 65,in new_method
    return method(self,other)
  File "C:\Users\AppData\Roaming\Python\Python39\site-packages\pandas\core\arraylike.py",line 113,in __truediv__
    return self._arith_method(other,operator.truediv)
  File "C:\Users\\AppData\Roaming\Python\Python39\site-packages\pandas\core\series.py",line 4998,in _arith_method
    result = ops.arithmetic_op(lvalues,rvalues,op)
  File "C:\Users\\AppData\Roaming\Python\Python39\site-packages\pandas\core\ops\array_ops.py",line 185,in arithmetic_op
    res_values = op(lvalues,rvalues)
  File "pandas\_libs\tslibs\timedeltas.pyx",line 1342,in pandas._libs.tslibs.timedeltas.Timedelta.__rtruediv__
numpy.core._exceptions.UFuncTypeError: ufunc 'true_divide' cannot use operands with types dtype('float64') and dtype('<m8[ns]')

解决方法

两个 datetime 对象相减产生一个 timedelta 对象。为了从 timedelta 对象中检索小时，您可以使用：

import numpy as np

hours = timedelta_object / np.timedelta64(1,"h")

注意：也可以是（更多熊猫风格）

hours = timedelta_object / pd.Timedelta(hours=1)

因此，在您的情况下，您可以将其用作：

appointments['Hours'] = (appointments['end'] - appointments['start']) / pd.Timedelta(hours=1)