如何解决如何在用户定义的公式中调用命名变量?使用 dplyr::summarise()
我正在尝试使用 ci.auc()
包中的 pROC
函数创建一个函数来提取“曲线下面积”估计的 2 个命名变量的置信区间,但它产生并出错:
Error in model.frame.default(formula = anchor,data = namedvar1,: 'data' must be a data.frame,environment,or list
。
如何解决这个问题?有没有更好的方法来指定从哪个数据框绘制命名变量?
原始代码工作正常:
library(pROC)
df <- structure(list(anchor1 = c(1,1,0),namedvar1 = c(0.603,-0.006,0.263,-0.089),namedvar2 = c(0.150346263678009,0.388250731888,-0.2579633906095,0.2562039253,0.139948502022,-0.267652844)),row.names = c(6L,7L,12L,13L,19L,29L),class = "data.frame")
# Base example with to extract CI bounds & estimate
as.numeric (ci.auc ( roc (df$anchor1,df$namedvar1,smooth = FALSE,direction = "<",ci = TRUE,boot.stratified = TRUE ) ) )
# Output looks good:
[1] 0.2908208 0.7777778 1.0000000
太好了,所以我将上述内容整合到我的函数中(我想为多个命名变量执行此操作):
### CREATE FUNC TO CALCULATE AUC and 95% CIs
new_roc <- function( df,anchor,na.rm = T) {
anchor <- enquo(anchor)
# Calculate and save this information as an object
dplyr::summarise(df,# ci.auc() & roc() are from pROC package
"Var1 AUC CIs" = as.numeric (ci.auc (roc (anchor,namedvar1,boot.stratified = TRUE ) ) ),"Var2 AUC CIs" = as.numeric (ci.auc (roc (anchor,namedvar2,boot.stratified = TRUE ) ) )
)
}
但是当我测试它时,我得到一个错误!
# Try the function
new_roc(df,anchor1 )
# Error output:
`Error in model.frame.default(formula = anchor,:'data' must be a data.frame,or list`
我试过 class(df)
,结果确实是 data.frame
,所以不确定是什么问题。
为了尝试隔离问题,我尝试了内部代码,但首先指定了数据框 - 不起作用:
# Doesn't work to pipe the df
df %>%
as.numeric (ci.auc (roc (anchor1,boot.stratified = TRUE ) ) )
## Produces error
Error in roc(anchor1,:
object 'anchor1' not found
也许我不必要地使用了 dplyr?是否有不同的方法来指定从哪个数据框绘制命名变量?谢谢!
我也尝试过放弃 dplyr 并直接调用数据帧,但也不起作用:
new_roc <- function( df,na.rm = T) {
anchor <- enquo(anchor)
# Calculate and save this information as an object
# ci.auc() & roc() are from pROC package
"Var1 AUC CIs" = as.numeric (ci.auc (roc (data[[anchor],data[[namedvar1],"Var2 AUC CIs" = as.numeric (ci.auc (roc (data[[anchor],data[[namedvar2],boot.stratified = TRUE ) ) )
)
}
# Produces a different Error:
Error in .subset2(x,i,exact = exact) :
invalid subscript type 'language'
解决方法
我们需要使用 !!
与 enquo
进行评估,或者可以将其修改为 {{}}
new_roc <- function( df,anchor,na.rm = TRUE) {
dplyr::summarise(df,`Var1 AUC CIs` = as.numeric (ci.auc (roc ({{anchor}},namedvar1,smooth = FALSE,direction = "<",ci = TRUE,boot.stratified = TRUE ) ) ),`Var2 AUC CIs` = as.numeric (ci.auc (roc ({{anchor}},namedvar2,boot.stratified = TRUE ) ) )
)
}
-测试
new_roc(df,anchor1)
#Setting levels: control = 0,case = 1
#Setting levels: control = 0,case = 1
# Var1 AUC CIs Var2 AUC CIs
#1 0.2908208 0.0000000
#2 0.7777778 0.3333333
#3 1.0000000 0.9866547
与
相同as.numeric (ci.auc ( roc (df$anchor1,df$namedvar1,boot.stratified = TRUE ) ) )
#Setting levels: control = 0,case = 1
#[1] 0.2908208 0.7777778 1.0000000
,
如果您不想使用 dplyr
方法,请尝试:
library(pROC)
new_roc <- function( df,anchor) {
data.frame(Var1_AUC_CIs = as.numeric(ci.auc(roc(df[[anchor]],boot.stratified = TRUE))),Var2_AUC_CIs = as.numeric(ci.auc(roc(df[[anchor]],df$namedvar2,boot.stratified = TRUE))))
}
new_roc(df,'anchor1')
# Var1_AUC_CIs Var2_AUC_CIs
#1 0.2908208 0.0000000
#2 0.7777778 0.3333333
#3 1.0000000 0.9866547
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