在平台消息回调期间抛出以下 RangeError

如何解决在平台消息回调期间抛出以下 RangeError

我在尝试保留退格以删除密码中的字符时遇到以下错误，当我尝试保留电子邮件时它没有给我错误。

这是以下错误：

====================================================================================================

======== Exception caught by services library ======================================================
The following RangeError was thrown during a platform message callback:
Value not in range: 9

When the exception was thrown,this was the stack: 
#0      _StringBase.substring (dart:core-patch/string_patch.dart:399:7)
#1      TextRange.textBefore (dart:ui/text.dart:2785:17)
#2      RenderEditable.delete (package:flutter/src/rendering/editable.dart:1119:37)
#3      _DeleteTextAction.invoke (package:flutter/src/widgets/default_text_editing_actions.dart:88:45)
#4      ActionDispatcher.invokeAction (package:flutter/src/widgets/actions.dart:518:21)
...
====================================================================================================

======== Exception caught by services library ======================================================
The following RangeError was thrown during a platform message callback:
Value not in range: 9

When the exception was thrown,this was the stack: 
#0      _StringBase.substring (dart:core-patch/string_patch.dart:399:7)
#1      TextRange.textBefore (dart:ui/text.dart:2785:17)
#2      RenderEditable.delete (package:flutter/src/rendering/editable.dart:1119:37)
#3      _DeleteTextAction.invoke (package:flutter/src/widgets/default_text_editing_actions.dart:88:45)
#4      ActionDispatcher.invokeAction (package:flutter/src/widgets/actions.dart:518:21)
...
====================================================================================================

这是我拥有的以下TextFormField：

DefaultTextFormField(
                    controller: passwordController,type: TextInputType.visiblePassword,suffix: controller.suffix,onSubmit: (value) {
                      if (_formKey.currentState.validate()) {
                        controller.signInWithEmailAndPassword();
                      }
                    },isPassword: controller.isPassword,suffixPressed: () {
                      controller.changePasswordVisibility();
                    },validate: (String value) {
                      if (value.isEmpty) {
                        return 'password is too short';
                      }
                    },label: 'Password',prefix: Icons.lock_outline,),

这是我用于通过电子邮件登录的以下方法：

  void signInWithEmailAndPassword() async {
    try {
      await _auth.signInWithEmailAndPassword(email: email,password: password);
      Get.offAll(HomeView());
    } catch (e) {
      print(e.message);
      Get.snackbar(
        'Error login account',e.message,colorText: Colors.black,snackPosition: SnackPosition.BOTTOM,);
    }
  }

因为我正在使用 GetX 状态管理..