如何解决收到意外的“ EXC_BAD_ACCESS”
| 当我从表格视图中删除单元格时:发生此错误:Program received signal: “EXC_BAD_ACCESS”.
warning: Unable to read symbols for /Xcode3.2.5/Platforms/iPhoneOS.platform/DeviceSupport/4.3.2 (8H7)/Symbols/Developer/usr/lib/libXcodeDebuggerSupport.dylib (file not found).
在这里,我从单元格中删除对象,并从日历中删除其事件:
if (editingStyle == UITableViewCellEditingStyleDelete)
{
//Get the object to delete from the array.
lovkid *mykids = (lovkid *)[appDelegate.actionarray1 objectAtIndex:indexPath.row];
appDelegate.actionId = mykids.Id;
//delete from calender
if( [ mykids.Event isEqualToString:@\"empty\"])
{
}
else
{
EKEvent* event2 = [appDelegate.eventStore eventWithIdentifier:mykids.Event];
if (event2 != nil)
{
NSError* error = nil;
[appDelegate.eventStore removeEvent:event2 span:EKSpanThisEvent error:&error];
}
}
//delete end
[mykids deleteAction];
[appDelegate.actionarray1 removeObjectAtIndex:indexPath.row];
//Delete the object from the table.
[localTable deleteRowsAtIndexPaths:[NSArray arrayWithObject:indexPath] withRowAnimation:UITableViewRowAnimationFade];
[localTable reloadData];
a = 0;
}
else
{
//NSLog(@\"test\");
}
从数据库删除:
deleteStmt1 = nil;
if(deleteStmt1 == nil)
{
const char *sql = \"delete from actions where id = ?\";
if(sqlite3_prepare_v2(database1,sql,-1,&deleteStmt1,NULL) != SQLITE_OK)
NSAssert1(0,@\"Error while creating delete statement. \'%s\'\",sqlite3_errmsg(database1));
//When binding parameters,index starts from 1 and not zero.
sqlite3_bind_int(deleteStmt1,1,(int)appDelegate.actionId);
if (SQLITE_DONE != sqlite3_step(deleteStmt1))
NSAssert1(0,@\"Error while deleting. \'%s\'\",sqlite3_errmsg(database1));
sqlite3_reset(deleteStmt1);
sqlite3_finalize(deleteStmt1);
}
出现此错误的原因是什么?
解决方法
我建议删除该行:
[localTable deleteRowsAtIndexPaths:[NSArray arrayWithObject:indexPath] withRowAnimation:UITableViewRowAnimationFade];
如果要按ѭ4重新加载表,则不必那样删除该行。该表将被重新加载以反映新的数据源状态。
另一方面,如果可以使表更平滑地刷新,则可以调查beginUpdates
和endUpdates
。在这种情况下,使用deleteRowsAtIndexPaths
是有意义的。
我不知道这是否可以解决您的崩溃问题。如果没有,我建议您在调试器下执行,这样您就可以准确地找出引起崩溃的令人讨厌的语句。
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