SQL Server 2005/2008 sumqty结果乘以连接

如何解决SQL Server 2005/2008 sumqty结果乘以连接

|| 我剩下两个表：T1列出所有已订购的物品，T2列出所有已装运的物品。我正在寻找一个结果集，该结果集将显示从T1订购的所有商品的数量以及从T2订购的相应发货数量。 当我在T1中检查一个订单的日期/订单/项目/数量信息时，它看起来像这样：

DATE                  |ORDER    |ITEM  |DESCRIPTION|QTY|CUSTOMER
01/01/2011 12:00:00 AM|123456789|123456|shoes      |1  |JANE
01/01/2011 12:00:00 AM|123456789|234567|shirt      |2  |TIM
01/01/2011 12:00:00 AM|123456789|345678|pants      |4  |JOE
01/01/2011 12:00:00 AM|123456789|123456|shoes      |9  |BOB

T2看起来像这样：

ORDER    |ITEM  |QTYSHIPPED|SHIPPED
123456789|123456|1         |01/10/2011 12:00:00 PM
123456789|234567|2         |01/10/2011 12:00:00 PM
123456789|345678|4         |01/10/2011 12:00:00 PM
123456789|123456|9         |01/10/2011 12:00:00 PM

我的查询如下：

select convert(varchar,a.date,101) as orderdate,a.order,a.item,a.description,sum(a.qty) as qty_ordered,convert(varchar,b.shipped,101) as shippeddate sum(b.qtyshipped) as qtyshipped
from T1 a --T1 is table with all items ordered
left join shipped T2 --T2 contains order #,qty shipped and shipped date
on a.order = b.order
group by convert(varchar,101),b.shipped

结果看起来像这样：

orderdate|order|item|description|qty_ordered|shippeddate|qtyshipped
01/01/2011|123456789|123456|20|01/10/2011|20
01/01/2011|123456789|234567|4|01/10/2011|20
01/01/2011|123456789|345678|8|01/10/2011|20

我希望看到的结果如下：

orderdate|order|item|description|qty_ordered|shippeddate|qtyshipped
01/01/2011|123456789|123456|10|01/10/2011|20
01/01/2011|123456789|234567|2|01/10/2011|20
01/01/2011|123456789|345678|4|01/10/2011|20

任何信息和帮助，将不胜感激！     

解决方法

我认为您还需要加入以下内容：

on a.order = b.order,a.item = b.item

    ,

WITH OrderDays AS (
  SELECT *,OrderDate = DATEADD(day,DATEDIFF(day,DATE),0)
  FROM T1
),ShippingDays AS (
  SELECT *,ShippingDate = DATEADD(day,SHIPPED),0)
  FROM T2
),OrdersGrouped AS (
  SELECT
    OrderDate,[ORDER],ITEM,DESCRIPTION,Qty = SUM(QTY)
  FROM OrderDays
  GROUP BY OrderDate,DESCRIPTION
),ShippingsGrouped AS (
  SELECT
    ShippingDate,QtyShipped = SUM(QTYHSHIPPED)
  FROM OrderDays
  GROUP BY ShippingDate,ITEM
)
SELECT
  o.*,s.ShippingDate,s.QtyShipped
FROM OrdersGrouped o
  LEFT JOIN ShippingsGrouped s ON o.[ORDER] = s.[ORDER] AND o.ITEM = s.ITEM

在不同日期发生的相同商品的运送将分别分组（并显示）。如果您希望将它们分组在一起，只需修改上面的

ShippingGrouped

CTE：

…
ShippingsGrouped AS (
  SELECT
    ShippingDate = MAX(ShippingDate),QtyShipped = SUM(QTYHSHIPPED)
  FROM OrderDays
  GROUP BY [ORDER],ITEM
)
…

ShippingDate

列将包含相应商品的最后发货日期。