MySQL查询在包含group by的派生表上进行联接，返回最近的相关记录

如何解决MySQL查询在包含group by的派生表上进行联接，返回最近的相关记录

|| 嗨，大家好我有一个MySQL查询，该查询在几个派生表上使用联接。派生查询之一效果很好，并且我得到的返回的行数正确。但是我还试图为每行显示相关表中的一些其他信息，这就是我在努力的地方。我在这里还阅读了其他几个类似的问题，但无法将其应用于查询。这是查询：

SELECT `adbookings`.`company_id`,`companies`.`company_name`,`adbookings`.`run`,`adbookings`.`bill_freq`,`adbookings`.`currency`,FORMAT(`adinserts`.`rate`,2) AS `rate`,`publications`.`title`,CONCAT(FLOOR(CAST(UNIX_TIMESTAMP()-`invoices`.`last_invoice_stamp` AS SIGNED INTEGER)/86400),\' days ago\') AS `last_invoice_days_ago`,`invoices`.`last_invoice_no`,`invoices`.`last_invoice_reference`
FROM `adinserts` 
INNER JOIN 
(
SELECT `publications`.`publication_id`,`publications`.`art_stamp`,`publications`.`title`
FROM `publications`
LEFT JOIN `adinserts` ON `publications`.`publication_id`=`adinserts`.`publication_id` AND `adinserts`.`invoice_id` IS NOT NULL
WHERE `publications`.`publication_stamp`>=UNIX_TIMESTAMP(\'2010-01-01 00:00:00\')
GROUP BY `publications`.`publication_id`
HAVING COUNT(`adinserts`.`invoice_id`)>0
) AS `publications` ON `adinserts`.`publication_id`=`publications`.`publication_id`
LEFT JOIN `adbookings` ON `adinserts`.`booking_id`=`adbookings`.`booking_id` 
LEFT JOIN
(
SELECT `company_id`,CONCAT_WS(\'\',`prefix`,`invoice_id`,`suffix`) AS `last_invoice_no`,MAX(`invoices`.`invoice_stamp`) AS `last_invoice_stamp`,`reference` AS `last_invoice_reference` 
FROM `invoices`
GROUP BY `invoices`.`company_id`
) AS `invoices` ON `adbookings`.`company_id`=`invoices`.`company_id`
LEFT JOIN `companies` ON `adbookings`.`company_id`=`companies`.`company_id` 
WHERE `adinserts`.`invoice_id` IS NULL AND `adinserts`.`cancel_stamp` IS NULL AND `adinserts`.`rate`>0
ORDER BY `publications`.`art_stamp`,`companies`.`company_name`

我的问题是第二个派生表...LEFT JOIN (...) AS invoices 我正在尝试使用MAX（invoice_stamp）获取该公司的最新相关发票的invoice_stamp。这似乎可以正常工作，并且确实会以invoice_stamp（Unix时间戳）的最大值返回相关记录。但是我也试图获取匹配的invoice_id和由MAX（）聚合函数返回的该记录的引用字段。但是invoice_id和reference字段与MAX（）函数返回的记录不匹配。有人知道如何获取派生表中聚合函数返回的记录的完整详细信息吗？

解决方法

基于AdInsert与出版物的比例为1：1，而与预订量（最终与公司）的比例为1：1，我们不需要反向链接到具有相同ID的AdInserts，就可以查找发票只是无视。这些应该是您正在寻找的合格广告插页，并最终想要有关预订/公司的其他信息。通过使用预查询来获取所有初步合格的广告插页和公司的最后盖章的发票，则可以通过该发票ID和时间戳将其加入发票。我没有得到“过去多少天”，但是希望您掌握了所有需要的信息，并在确认此查询完成了工作（或大部分）后可以重新计算。由于我可以直接链接到单个发票，因此无需将字段合并为单个字段，而是将它们作为个人保留...同样，您可以根据需要进行调整。

SELECT STRAIGHT_JOIN
      PreQuery.Company_ID,PreQuery.Company_Name,PreQuery.Run,PreQuery.Bill_Freq,PreQuery.Currency,PreQuery.Rate,PreQuery.Publication_ID,PreQuery.Booking_ID,PreQuery.Art_Stamp,PreQuery.Title,Invoices.prefix,Invoices.invoice_id,Invoices.suffix,Invoices.invoice_stamp,Invoices.reference 
   from 
      ( SELECT 
              ab.company_id,c.Company_Name
              ab.run,ab.bill_freq,ab.currency,ai.publication_id,ai.booking_id,format( ai.rate,2 ) Rate,p.title,p.art_stamp,( select MAX( invoices.invoice_stamp ) 
                    from Invoices 
                    where Invoices.Company_ID = c.Company_ID ) As LastInvoiceStamp;
           from
              adinserts ai
                 JOIN publications p
                    ON ai.publication_id = p.publication_id
                    and p.publication_stamp >= UNIX_TIMESTAMP(\'2010-01-01 00:00:00\'

                 JOIN adBookings ab
                    ON ai.Booking_ID = ab.Booking_ID

                    JOIN Company c
                       ON ab.Company_id = c.Company_ID

           where
                  ai.Invoice_ID is null
              and ai.Cancel_Stamp is null
              and ai.rate > 0 ) PreQuery

      LEFT JOIN Invoices
         ON PreQuery.Company_ID = Invoices.Company_ID
         AND PreQuery.LastInvoiceStamp = Invoices.Invoice_Stamp

您可能需要将COALESCE（）应用于发票字段（如果为null的情况下），而该公司之前没有发票，但是我认为这与您要查找的内容非常接近。 , 好的，这是另一个似乎可以返回我想要的方法的方法。虽然它使我身体痛苦，但不得不诉诸于这样的事情...

SELECT `adbookings`.`company_id`,`companies`.`company_name`,`adbookings`.`run`,`adbookings`.`bill_freq`,`adbookings`.`currency`,FORMAT(`adinserts`.`rate`,2) AS `rate`,`publications`.`title`,CONCAT(FLOOR(CAST(UNIX_TIMESTAMP()-SUBSTRING_INDEX(`invoices`.`last_invoice`,\'-\',1) AS SIGNED INTEGER)/86400),\' days ago\') AS `last_invoice_days_ago`,SUBSTRING_INDEX( SUBSTRING_INDEX(`invoices`.`last_invoice`,3),-1) AS `last_invoice_no`,4),-1) AS `last_invoice_reference` 
FROM `adinserts` 
INNER JOIN 
(
SELECT `publications`.`publication_id`,`publications`.`art_stamp`,`publications`.`title`
FROM `publications`
LEFT JOIN `adinserts` ON `publications`.`publication_id`=`adinserts`.`publication_id` AND `adinserts`.`invoice_id` IS NOT NULL
WHERE `publications`.`publication_stamp`>=UNIX_TIMESTAMP(\'2010-01-01 00:00:00\')
GROUP BY `publications`.`publication_id`
HAVING COUNT(`adinserts`.`invoice_id`)>0
) AS `publications` ON `adinserts`.`publication_id`=`publications`.`publication_id`
LEFT JOIN `adbookings` ON `adinserts`.`booking_id`=`adbookings`.`booking_id` 
LEFT JOIN
(
SELECT `company_id`,MAX(CONCAT_WS(\'-\',`invoice_stamp`,`invoice_id`,CONCAT_WS(\'\',`prefix`,`suffix`),`reference`)) AS `last_invoice` 
FROM `invoices`
GROUP BY `invoices`.`company_id`
) AS `invoices` ON `adbookings`.`company_id`=`invoices`.`company_id`
LEFT JOIN `companies` ON `adbookings`.`company_id`=`companies`.`company_id` 
WHERE `adinserts`.`invoice_id` IS NULL AND `adinserts`.`cancel_stamp` IS NULL AND `adinserts`.`rate`>0
ORDER BY `publications`.`art_stamp`,`companies`.`company_name`

因此，在第二个派生表中，我正在运行从特定行中合并所需数据的操作，然后在该行上运行MAX（）。然后在父查询中，根据我的距离，使用子字符串函数“爆炸”。这是在关系数据库中必须采取的一种可怕的方法：( 但这有效:)

MySQL查询在包含group by的派生表上进行联接，返回最近的相关记录

如何解决MySQL查询在包含group by的派生表上进行联接，返回最近的相关记录

解决方法

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