如何解决显示send_invitations.class不能解析为android中的类型
|| hai all ... 我正在将所有仿真器联系人显示在我的appliaction中。我想选择一些联系人并将其放入数组...我遵循以下代码...请帮助我。package com.android.sample;
import android.app.Activity;
import android.content.Intent;
import android.database.Cursor;
import android.net.Uri;
import android.os.Bundle;
import android.provider.ContactsContract;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.Toast;
public class selectedcontacts extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button existing_contacts = (Button)findViewById(R.id.btn_contact_existing);
existing_contacts.setOnClickListener(new OnClickListener() {
public void onClick(View v){
Intent intent_contacts = new Intent(Intent.ACTION_PICK,ContactsContract.Contacts.CONTENT_URI);
/*contacts.setAction(android.content.Intent.ACTION_VIEW);
contacts.setData(People.CONTENT_URI);*/
startActivityForResult(intent_contacts,0);
//displayContacts();
}
});
}
protected void onActivityResult(int requestCode,int resultCode,Intent data)
{
super.onActivityResult(requestCode,resultCode,data);
String name,mailid,id;
switch(requestCode)
{
case 0:
{
if(resultCode == RESULT_OK )
{
Uri contactdata = data.getData();
Cursor cur = managedQuery(contactdata,null,null);
if(cur.moveToFirst())
{
id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
Cursor emailCur = getContentResolver().query(ContactsContract.CommonDataKinds.Email.CONTENT_URI,ContactsContract.CommonDataKinds.Email.CONTACT_ID + \" = ?\",new String[]{id},null);
emailCur.moveToFirst();
String email = emailCur.getString(emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
name = cur.getString(cur.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
//mailid = cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
//mailid = cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Email._ID));
// Toast.makeText(context_contact,\"Name:\"+name+\"\\nmailid:\"+email,Toast.LENGTH_SHORT).show();
Intent intent_add_invitees = new Intent(Contact.this,Send_invitations.class);
intent_add_invitees.putExtra(\"invitee_name\",name);
intent_add_invitees.putExtra(\"invitee_mailid\",email);
setResult(RESULT_OK,intent_add_invitees);
finish();
}
}
}
}
}
}
有人告诉我如何将选定的联系人(使用复选框)放入数组的方式
解决方法
查看我对帖子的回答
public static void getContactNumbers(Context context) {
String contactNumber = null;
int contactNumberType = Phone.TYPE_MOBILE;
String nameOfContact = null;
if (ApplicationConstants.phoneContacts.size() <= 0) {
ContentResolver cr = context.getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,null,null);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
String id = cur.getString(cur
.getColumnIndex(BaseColumns._ID));
nameOfContact = cur
.getString(cur
.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (Integer
.parseInt(cur.getString(cur
.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
Cursor phones = cr
.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,ContactsContract.CommonDataKinds.Phone.CONTACT_ID
+ \" = ?\",new String[] { id },null);
while (phones.moveToNext()) {
contactNumber = phones.getString(phones
.getColumnIndex(Phone.NUMBER));
contactNumberType = phones.getInt(phones
.getColumnIndex(Phone.TYPE));
Log.i(TAG,\"...Contact Name ....\" + nameOfContact
+ \"...contact Number...\" + contactNumber);
}
phones.close();
}
}
}// end of contact name cursor
cur.close();
}
}
谢谢
迪帕克
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