如何解决找出每一行的最大值
| 这是我的问题的简化版本。有两个表,一个有机器,第二个有关于其状态更改的信息(带有日期参考)(实际上不是日期,而是班次索引,这就是为什么我必须进行另一个查询才能获取日期本身的原因)。 我想获取每台计算机的最后状态。 我的查询是:SELECT * FROM machines
LEFT JOIN (SELECT * FROM statechange,dates WHERE....ORDER BY date DESC LIMIT 0,1) AS state
ON state.mid=machines.mid
但由于查询,我只能得到一台机器。
不创建视图怎么办?
解决方法
select m.*,s.`date` from machines as m
inner join (
select mid,`date`
from statechange
order by `date` desc) as s
on m.mid = s.mid
group by m.mid
, 通过执行以下操作,您将获得每台计算机的最新状态更改。
SELECT mid,max(date)
FROM statechange
GROUP BY mid
然后加入该连接,以获取每台计算机的当前状态。 (猜测列名。)
SELECT m.*,sc.state,sc.date
FROM machines m
INNER JOIN statechange sc
ON ( sc.mid = m.mid )
INNER JOIN (
SELECT mid,MAX(date) date
FROM statechange
GROUP BY mid
) s
ON ( (s.mid = sc.mid) and (s.date = sc.date) );
我认为查看每台计算机的当前状态可能很有用。
, 假设statechange
表的主键是Max有意义的东西(如整数)
Select ...
From Machines As M
Left Join (
Select S1.mid,Max( S1.PrimaryKeyCol ) As PrimaryKeyCol
From statechange As S1
Join dates As D1
On D1.statechangeFK = S1.PrimaryKeyCol
Where D1.date = (
Select Max( D2.date )
From dates As D2
Where D2.statechangeFK = D1.statechangeFK
)
Group By S1.mid
) As LastStateChange
On LastStateChange.mid = M.mid
Left Join statechange As S
On S.PrimaryKeyCol = LastStateChange.PrimaryKeyCol
如果您想从statechange表返回列,则最后一个联接。
根据其他信息进行修订
Select ...
From Machines As M
Left Join (
Select S1.mid,Max( S1.PrimaryKeyCol ) As PrimaryKeyCol
From dates As D1
Join statechange As S1
On S1.DatesForeignKeyCol = D1.PrimaryKeyCol
Where D1.date = (
Select Max( D2.date )
From dates As D2
Join statechange As S2
On S2.DatesForeignKeyCol = D2.PrimaryKeyCol
Where S2.mid = S1.mid
)
Group By S1.mid
) As LastStateChange
On LastStateChange.mid = M.mid
Left Join statechange As S
On S.PrimaryKeyCol = LastStateChange.PrimaryKeyCol
Left Join dates As D
On D.PrimaryKeyCol = S.DatesForeignKeyCol
我使用上述方法的原因之一是要考虑以下情况:对于相同的mid
和date
值,您可能有多个statechange
行。在这种情况下,以上方法将使用主键列作为决胜局。
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