如何使用Android在后台发送短信？

如何解决如何使用Android在后台发送短信？

| 我来自iPhone开发，您在不要求用户确认发送的情况下无法在后台发送SMS。可以在android中在后台发送短信，从而无需用户干预吗？     

解决方法

        发送带有短信传递通知的短信作为吐司。 方法调用如下。

sendSMS(\"98********\",\"This is test message\");

方法签名如下。

/*
 * BroadcastReceiver mBrSend; BroadcastReceiver mBrReceive;
 */
private void sendSMS(String phoneNumber,String message) {
    ArrayList<PendingIntent> sentPendingIntents = new ArrayList<PendingIntent>();
    ArrayList<PendingIntent> deliveredPendingIntents = new ArrayList<PendingIntent>();
    PendingIntent sentPI = PendingIntent.getBroadcast(mContext,new Intent(mContext,SmsSentReceiver.class),0);
    PendingIntent deliveredPI = PendingIntent.getBroadcast(mContext,SmsDeliveredReceiver.class),0);
    try {
        SmsManager sms = SmsManager.getDefault();
        ArrayList<String> mSMSMessage = sms.divideMessage(message);
        for (int i = 0; i < mSMSMessage.size(); i++) {
            sentPendingIntents.add(i,sentPI);
            deliveredPendingIntents.add(i,deliveredPI);
        }
        sms.sendMultipartTextMessage(phoneNumber,null,mSMSMessage,sentPendingIntents,deliveredPendingIntents);

    } catch (Exception e) {

        e.printStackTrace();
        Toast.makeText(getBaseContext(),\"SMS sending failed...\",Toast.LENGTH_SHORT).show();
    }

}

现在，另外两个类SmsDeliveredReceiver，SmsSentReceiver如下。

public class SmsDeliveredReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context,Intent arg1) {
    switch (getResultCode()) {
    case Activity.RESULT_OK:
        Toast.makeText(context,\"SMS delivered\",Toast.LENGTH_SHORT).show();
        break;
    case Activity.RESULT_CANCELED:
        Toast.makeText(context,\"SMS not delivered\",Toast.LENGTH_SHORT).show();
        break;
    }
}

} 现在是SMSSentReceiver。

public class SmsSentReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context,\"SMS Sent\",Toast.LENGTH_SHORT).show();

        break;
    case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
        Toast.makeText(context,\"SMS generic failure\",Toast.LENGTH_SHORT)
                .show();

        break;
    case SmsManager.RESULT_ERROR_NO_SERVICE:
        Toast.makeText(context,\"SMS no service\",Toast.LENGTH_SHORT)
                .show();

        break;
    case SmsManager.RESULT_ERROR_NULL_PDU:
        Toast.makeText(context,\"SMS null PDU\",Toast.LENGTH_SHORT).show();
        break;
    case SmsManager.RESULT_ERROR_RADIO_OFF:
        Toast.makeText(context,\"SMS radio off\",Toast.LENGTH_SHORT).show();
        break;
    }
}

} 现在，权限打开您的AndroidManifest.xml并添加以下行

<uses-permission android:name=\"android.permission.SEND_SMS\"/>

和它的完成...。     ,        是的，你也有能力。

SmsManager sm = SmsManager.getDefault(); 
sm.sendTextMessage(number,message,null); 

    ,        请参阅http://thinkandroid.wordpress.com/2010/01/08/sending-sms-from-application/。您将需要适当的权限。     ,        最佳答案是好的，但是在API级别23以上，您将需要务实地获得许可。否则，每次都会提示权限。

 private static final int PERMISSION_REQUEST_CODE = 1;

if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.M) {

    if (checkSelfPermission(Manifest.permission.SEND_SMS)
            == PackageManager.PERMISSION_DENIED) {

        Log.d(\"permission\",\"permission denied to SEND_SMS - requesting it\");
        String[] permissions = {Manifest.permission.SEND_SMS};

        requestPermissions(permissions,PERMISSION_REQUEST_CODE);

    }
}