如何解决美国电话号码验证问题
| 我上课的这段代码有麻烦：这是问题所在 1.）成功后不会循环播放 （代码可以编译，但是当它询问“您的电话号码是什么？”并且我输入909-8930时，输出只会回答：correct直到退出（带有电话号码）。我是在假设它应该循环吗？ ） 2.）由于括号中的原因，给出了错误：phone = phone.replaceAll(\"(\",\"\");
phone = phone.replaceAll(\")\",\"\");
phone = phone.replaceAll(\"-\",\"\");
/*
*/
import java.util.Scanner; //
public class PhoneNumber
{
//********number()******
public static boolean Number(String str)
{
int n=0;
while(n<str.length()) //while condition for the loop
{
char c=str.charAt(n);
if(!(c>=\'0\'&&c<=\'9\'))return(false);//0 to 9
n++; // counter and checked loop?
}
return (true);
}
// Phone Number
public static void main(String[] args)
{
// Create a Scanner object to read input.
String phone;
Scanner sc = new Scanner(System.in);
// Get the favorite city
System.out.print(\"What is your phone number?\"); // no ln
phone=sc.nextLine( );
//replace all perenthesis and dashes
phone = phone.replaceAll(\"-\",\"\");
phone = phone.replaceAll(\"(\",\"\");
phone = phone.replaceAll(\")\",\"\");
// validation of number
if(Number(phone))
{
// sub stuff to add back the dash and whateves
String first,middle,last;
first = phone.substring (0,3);
middle = phone.substring (3,6);
last = phone.substring (6);
String phonea = \"(\"+ first + \")\" +\"-\"+middle+ \"-\"+last;
// print stuff back
System.out.println (\"correct until exit\"+ phonea);
// condition to exit
if (phone.equalsIgnoreCase(\"quit\")); //not working?
if (phone.equalsIgnoreCase(\"end\"));
if (phone.equalsIgnoreCase(\"stop\"))System.exit(0);
}
else
{
System.err.println(\"error-incorrect format: \"+ phone); //error
}
}
}
解决方法
终止应用程序的原因与确定应用程序的下一个状态应该如何有关。查看正确电话号码大小写结尾处的代码：
// print stuff back
System.out.println (\"correct until exit\"+ phonea);
// condition to exit
if (phone.equalsIgnoreCase(\"quit\")); //not working?
if (phone.equalsIgnoreCase(\"end\"));
if (phone.equalsIgnoreCase(\"stop\"))
System.exit(0);
String
phone
System.out.println(\"What would you like to do?\");
String nextState = sc.nextLine();
while (!nextState.equals(\"quit\") && !nextState.equals(\"exit\")) {
//Do what you need to do (read the phone number,validate it,etc)
System.out.println(\"What would you like to do?\");
String nextState = sc.nextLine();
}
System.out.println(\"End of application\");
while (!phone.equalsIgnoreCase(\"quit\")) {
}
if (phone.equalsIgnoreCase(\"quit\")); //remove the semicolon in this line,otherwise System.exit will never be called.
correct
phone = phone.replaceAll(\"(\",\"\");
replaceAll
\"(\"
replaceAll
(
(
\\
\\(
\"\\(\"
\\
phone = phone.replaceAll(\"\\\\(\",\"\");
if
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