如何解决带有评论类型评论的问题
| 大家好，我想知道我是否可以在我为一个项目构建的网站上获得一些帮助。它几乎完成了，但是我正在努力进行其中的一部分，这基本上是评论。 我正在创建一个电影评论网站，有点像IMDB.com，但我的课程只适合上课，但是我真的很努力地工作。 对我来说，理想的情况是让某人能够键入他们想要搜索的电影，然后在他们提交后将他们带到另一个页面。在该页面上，电影信息，例如电影名称，描述，类型，等级等。然后在其下，回顾人们对电影的看法。但是，我无法获得的一件事是，当有人键入Avatar时，会出现电影评论，但是当他们键入Ghost Rider时，会出现完全相同的评论，如果可以的话，我希望他们分开。 对于我的桌子， 电影MovieID,Description,Rating,Genre
ReviewID,Name,Review,MovieID
<?php require_once(\'../Connections/lesson6.php\'); ?>
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$MM_restrictGoTo = $MM_restrictGoTo. $MM_qsChar . \"accesscheck=\" . urlencode($MM_referrer);
header(\"Location: \". $MM_restrictGoTo);
exit;
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<?php
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function GetSQLValueString($theValue,$theType,$theDefinedValue = \"\",$theNotDefinedValue = \"\")
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}
$colname_GetMovie = \"-1\";
if (isset($_GET[\'Search\'])) {
$colname_GetMovie = $_GET[\'Search\'];
}
mysql_select_db($database_lesson6,$lesson6);
$query_GetMovie = sprintf(\"SELECT * FROM movie WHERE MovieName = %s\",GetSQLValueString($colname_GetMovie,\"text\"));
$GetMovie = mysql_query($query_GetMovie,$lesson6) or die(mysql_error());
$row_GetMovie = mysql_fetch_assoc($GetMovie);
$totalRows_GetMovie = mysql_num_rows($GetMovie);
mysql_select_db($database_lesson6,$lesson6);
$current_MovieID=MovieID;
$query_Recordset1 = \"SELECT * FROM reviews WHERE MovieID=$current_MovieID\";
$Recordset1 = mysql_query($query_Recordset1,$lesson6) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
?>
<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Transitional//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\">
<html xmlns=\"http://www.w3.org/1999/xhtml\">
<head>
<meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />
<title>Results</title>
<link href=\"styles/style_sheet.css\" rel=\"stylesheet\" type=\"text/css\" />
<style type=\"text/css\">
a:link {
color: #0F0;
}
a:visited {
color: #0F0;
}
</style>
</head>
<body>
<div id=\"main_container\">
<div id=\"header\">
</div><!--End of header-->
<div class=\"shadow\">
<div id=\"navbar\"><a href=\"index.php\">Home</a> <a href=\"register.php\">Register</a> <a href=\"login.php\">Login</a> / <a href=\"<?php echo $logoutAction ?>\">Logout</a> <a href=\"Search.php\">Search</a></div><!--End of NavBar-->
</div><!--End of navbar shadow-->
<br />
<div class=\"shadow\">
<div id=\"Content\">
<h2> Results:</h2>
<?php if ($totalRows_GetMovie == 0) { // Show if recordset empty ?>
<form id=\"form1\" name=\"form1\" method=\"post\" action=\"\">
Sorry,there was no movie with that name in the database. Click <a href=\"Search.php\">here</a> to search again.
</form>
<?php } // Show if recordset empty ?>
<p> </p>
<?php if ($totalRows_GetMovie > 0) { // Show if recordset not empty ?>
<form action=\"\" name=\"Movie_Search\"method=\"get\">
<p>Movie Name: <?php echo $row_GetMovie[\'MovieName\']; ?></p>
<p> Movie Description: <?php echo $row_GetMovie[\'Description\']; ?></p>
<p>Genre: <?php echo $row_GetMovie[\'Genre\']; ?></p>
<p>Rating: <?php echo $row_GetMovie[\'Rating\']; ?></p>
<p> </p>
</form>
<?php } // Show if recordset not empty ?>
<label for=\"movie_search\"></label>
<form action=\"\" method=\"get\">
<center><h2>Reviews</h2></center>
<?php do { ?>
<table width=\"566\">
<tr>
<td width=\"20\" height=\"97\"><p><img src=\"Pictures/Male-User-icon.png\" width=\"67\" height=\"67\" /></p></td>
<td width=\"534\"><p> <?php echo $row_Recordset1[\'Name\']; ?> says:</p>
<p><?php echo $row_Recordset1[\'Review\']; ?></p>
<p>-------------------------------------------------------------------------------------------------</p></td>
</tr>
</table>
<?php } while ($row_Recordset1 = mysql_fetch_assoc($Recordset1)); ?>
<p> </p>
<p> </p>
<form id=\"insert_comments\" s style=\"border:thin\" name=\"insert_comments\" method=\"POST\"first_name\">
First Name:</label>
<br />
<input type=\"text\" name=\"first_name\" id=\"first_name\" />
<br>
<label for=\"desc\">Comments:<br /></label>
<textarea name=\"comments\" id=\"comments\" cols=\"45\" rows=\"5\"></textarea>
</p>
<p>
<input type=\"submit\" name=\"submit\" id=\"submit\" value=\"Submit\" />
</p>
</form>
<p> </p>
</div>
<!--End of Contentr-->
</div><!--End of content shadow-->
<div class=\"footer\">
<hr />© Nate Christensen<hr />
</div><!--End of footer-->
</div><!--End of Main Container-->
</body>
</html>
<?php
mysql_free_result($GetMovie);
mysql_free_result($Recordset1);
?>
解决方法
评论表包含评论，对不对？我可以看到那里有一个MovieID列，因此您应该能够以条件
WHERE MovieID = \'$current_movie_id\'
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