id是python中的关键字吗？

如何解决id是python中的关键字吗？

| 我的编辑器（TextMate）以其他颜色（当用作变量名时）显示）0ѭ，而不是通常的变量名。是关键字吗？我不想给任何关键字加上阴影...     

解决方法

        

id

不是Python中的关键字，而是内置函数的名称。 关键字是：

and       del       from      not       while
as        elif      global    or        with
assert    else      if        pass      yield
break     except    import    print
class     exec      in        raise
continue  finally   is        return
def       for       lambda    try

关键字是无效的变量名。以下是语法错误：

if = 1

另一方面，诸如

id

或

type

或

str

之类的内置函数可能会被遮盖：

str = \"hello\"    # don\'t do this

    ,        您还可以从python获得帮助：

>>> help(id)
Help on built-in function id in module __builtin__:

id(...)
    id(object) -> integer

    Return the identity of an object.  This is guaranteed to be unique among
    simultaneously existing objects.  (Hint: it\'s the object\'s memory address.)

或者，您可以质疑IPython

IPython 0.10.2   [on Py 2.6.6]
[C:/]|1> id??
Type:           builtin_function_or_method
Base Class:     <type \'builtin_function_or_method\'>
String Form:    <built-in function id>
Namespace:      Python builtin
Docstring [source file open failed]:
    id(object) -> integer

Return the identity of an object.  This is guaranteed to be unique among
simultaneously existing objects.  (Hint: it\'s the object\'s memory address.)

    ,        仅供参考： 检查Python中是否有关键字：

>>> import keyword  
>>> keyword.iskeyword(\'id\')
False

检查Python中的所有关键字：

>>> keyword.kwlist
[\'and\',\'as\',\'assert\',\'break\',\'class\',\'continue\',\'def\',\'del\',\'elif\',\'else\',\'except\',\'exec\',\'finally\',\'for\',\'from\',\'global\',\'if\',\'import\',\'in\',\'is\',\'lambda\',\'not\',\'or\',\'pass\',\'print\',\'raise\',\'return\',\'try\',\'while\',\'with\',\'yield\']

    ,        这是一个内置函数：

id(...)
    id(object) -> integer

    Return the identity of an object.  This is guaranteed to be unique among
    simultaneously existing objects.  (Hint: it\'s the object\'s memory address.)