使用Pentaho获得表中所有td的XPath

如何解决使用Pentaho获得表中所有td的XPath

|| 无论如何，有没有使用Pentaho从html页面解析表td \的表？可以说我有这个html内容

<html>
  <body>
    <table>
      <tr>
        <td>info1</td>
        <td>info2</td>
      </tr>
      <tr>
        <td>info3</td>
        <td>info4</td>
      </tr>
    </table>
  </body>
</html>

我在Pentaho中使用“从XML获取数据”和以下数据：

Content::
Loop XPath: /html/body/table/tr
Fields::
Name: tableData
XPath: td

我想要的数据信息是 info1 info2 info3 info4以任何方式。任何帮助将不胜感激！

解决方法

我通过将文件的每一行都读取为行来解决了。然后，我添加了一个Pentaho步骤\“ User Defined Java Class \”，并使其使用XSLT将表内容解析为一个新的XML文件。使用该XML，我能够获得完成任务所需的数据。这是我在“用户定义的Java类”中写的内容：

import java.util.*;
import java.io.FileOutputStream;

import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;

private int infilenameIndex;
private int xsltfilenameIndex;
private int outfilenameIndex;


public boolean processRow(StepMetaInterface smi,StepDataInterface sdi) throws KettleException {
  Object[] r=getRow();
  if (r==null) {
    setOutputDone();
    return false;
  }


  if (first == false) {
     infilenameIndex = getInputRowMeta().indexOfValue(getParameter(\"infilename\"));
     if (infilenameIndex < 0) {
         throw new KettleException(\"Field not found in the input row,check parameter \'infilename\'!\");
     }
     xsltfilenameIndex = getInputRowMeta().indexOfValue(getParameter(\"xsltfilename\"));
     if (xsltfilenameIndex < 0) {
         throw new KettleException(\"Field not found in the input row,check parameter \'xsltfilename\'!\");
     }
     outfilenameIndex = getInputRowMeta().indexOfValue(getParameter(\"outfilename\"));
     if (outfilenameIndex < 0) {
         throw new KettleException(\"Field not found in the input row,check parameter \'outfilename\'!\");
     }

     first=false;
  }

  String infilename = get(Fields.In,\"infilename\").getString(r);
  String xsltfilename = get(Fields.In,\"xsltfilename\").getString(r);
  String outfilename = get(Fields.In,\"outfilename\").getString(r);

  Object[] outputRowData = RowDataUtil.resizeArray(r,data.outputRowMeta.size());
  int outputIndex = getInputRowMeta().size();

  transform(infilename,xsltfilename,outfilename);


  putRow(data.outputRowMeta,outputRowData);

  return true;
}
public void transform(String infilename,String xsltfilename,String outfilename) throws KettleException {

    javax.xml.transform.stream.StreamSource inss = null;
    javax.xml.transform.stream.StreamSource xsltss = null;
    javax.xml.transform.stream.StreamResult outss = null;

    logBasic(\"\");
    logBasic(\"Transformerar \" +  infilename + \" med \" + xsltfilename + \" till \" + outfilename );
    logBasic(\"\");

    try {
       inss = new javax.xml.transform.stream.StreamSource(infilename);
    }     
    catch (Exception e) {
       logError(\"Infil saknas \" +  infilename);
       throw new KettleException(e);
    }

    try {
       xsltss = new javax.xml.transform.stream.StreamSource(xsltfilename);
    }     
    catch (Exception e) {
       logError(\"Xsltfil saknas \" +  xsltfilename);
       throw new KettleException(e);
    }

    try {
       outss = new javax.xml.transform.stream.StreamResult(outfilename);
    }     
    catch (Exception e) {
       logError(\"Outfil saknas \" +  outfilename);
       throw new KettleException(e);
    }

    try {       
        TransformerFactory tFactory = TransformerFactory.newInstance();

        // Set the TransformerFactory to the SAXON implementation.
        //tFactory = new net.sf.saxon.TransformerFactoryImpl();

        Transformer transformer = tFactory.newTransformer(xsltss);

        // Do the transfromtation
        transformer.transform(inss,outss);
    }
    catch (Exception e) {
       throw new KettleException(e);
    }
    return;
}

,看到了对于现在要来这里的人。可以使用jsoup使用适当的路径来解析为xml。它是一个简单的插件，可以与其他方法一起在用户定义的类中使用。这是一个CSS选择器。

使用Pentaho获得表中所有td的XPath

如何解决使用Pentaho获得表中所有td的XPath

解决方法

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