SQL Server 2008:复杂插入

如何解决SQL Server 2008:复杂插入

| 我有一张叫ѭ0的表:
BeginYear  |   EndYear   |    Name
1974           1983           Robert
对于
Employees
中的每条记录,我需要将每年插入到名为
EmployeeYears
的新表中 所以:
For Each Record in Employees
    For i as int = Begin Year to End year
        INSERT i,Name into EmployeeYears
在SQL中执行此操作的任何方法...可能使用游标吗?     

解决方法

其要旨是使用WITH语句创建所有记录并将其插入到最终表中。
;WITH q AS (
  SELECT Year = BeginYear,Name
  FROM   Employees
  UNION ALL
  SELECT q.Year + 1,q.Name
  FROM   q
         INNER JOIN Employees e ON e.Name = q.Name
                                   AND e.EndYear > q.Year
)
INSERT INTO EmployeeYears
SELECT * FROM q
OPTION(MAXRECURSION 0)
测试数据
CREATE TABLE Employees (BeginYear INTEGER,EndYear INTEGER,Name VARCHAR(32))
CREATE TABLE EmployeeYears (Year INTEGER,Name VARCHAR(32))

INSERT INTO Employees
  SELECT 1974,1976,\'Robert\'
  UNION ALL SELECT 1972,1975,\'Lieven\'
结果
SELECT  *
FROM    EmployeeYears
ORDER BY Name,Year

1972    Lieven
1973    Lieven
1974    Lieven
1975    Lieven
1974    Robert
1975    Robert
1976    Robert
    ,如果您有数字表,则可以加入该表以获取各个年份的记录,并避免使用光标。我只是用从1965年到968年的数字填充了数字表,但是一个realife数字表(出于示例目的,它也不会是一个临时表,如下所示,但它存在于您的模式中)可能会有几百万条记录对于很多比较有用。
create table #Numbers (Number int)
insert into #Numbers
select 1965
union
select 1966
union 
select 1967
union 
select 1968

create table #employees (name varchar (50),beginyear int,endyear int)
insert into #employees
select \'Dick\',1966,1968
union all 
select \'harry\',1965,1967
union all 
select \'tom\',1955,1966

insert into EmployeeYears (Name,[Year])
select Name,n.number 
from #Employees e
join #Numbers n on  n.number between e.beginyear and e.endyear
order by name
    ,是的,您实际上必须做一个循环...我宁愿不使用CURSORS,但这种情况sorta还是有道理的...无论如何,这里的代码只是一个直接循环,向您展示了您可以做的事情SQL中的这种代码:
DECLARE @Employee VARCHAR(100)
DECLARE @BeginYear INT,@EndYear INT,@i INT

SET @Employee = \'\'

WHILE (1=1)
BEGIN
    SET @Employee = (SELECT TOP 1 Name FROM Employees ORDER BY Name WHERE Name > @Employee)

    IF @Employee IS NULL BREAK

    SELECT @BeginYear = BeginYear,@EndYear = EndYear FROM Employees WHERE Name = @Employee

    SET @i = @BeginYear

    WHILE (@i <= @EndYear)
    BEGIN
        INSERT INTO EmployeeYears (Year,Name) VALUES (@i,@Employee)
        SET @i = @i + 1
    END
END
    ,您可以使用递归CTE:
;WITH CTE AS
(
    SELECT BeginYear,EndYear,Name
    FROM Employees
    UNION ALL
    SELECT BeginYear+1,Name
    FROM CTE 
    WHERE BeginYear < EndYear
)  
INSERT INTO EmployeeYears (Year,Name)
SELECT BeginYear,Name
FROM CTE 
ORDER BY Name,BeginYear
OPTION(MAXRECURSION 0)
    ,您可以使用递归过程。就像一个波纹管:
CREATE Procedure InsertYear
    @Name ....
    @BeginYear ...
    @EndYear ...
AS
{
     INSERT INTO  EmployeeYears  VALUES(@BeginYear,@Name);
     SET  @BeginYear = @BeginYear + 1
     IF @BeginYear < @EndYear
     BEGIN
         InsertYear(@Name,@BeginYear,@EndYear)
     END

     RETURN
}
    ,您可以这样做,但是如果Begin或end超过2047,它将失败
INSERT INTO EmployeeYears (number,name)
SELECT v.number,e.name
FROM 
    Employees e
    INNER JOIN master..spt_values v on 
    v.number between beginYear and endYear
    

版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。

相关推荐


依赖报错 idea导入项目后依赖报错,解决方案:https://blog.csdn.net/weixin_42420249/article/details/81191861 依赖版本报错:更换其他版本 无法下载依赖可参考:https://blog.csdn.net/weixin_42628809/a
错误1:代码生成器依赖和mybatis依赖冲突 启动项目时报错如下 2021-12-03 13:33:33.927 ERROR 7228 [ main] o.s.b.d.LoggingFailureAnalysisReporter : *************************** APPL
错误1:gradle项目控制台输出为乱码 # 解决方案:https://blog.csdn.net/weixin_43501566/article/details/112482302 # 在gradle-wrapper.properties 添加以下内容 org.gradle.jvmargs=-Df
错误还原:在查询的过程中,传入的workType为0时,该条件不起作用 &lt;select id=&quot;xxx&quot;&gt; SELECT di.id, di.name, di.work_type, di.updated... &lt;where&gt; &lt;if test=&qu
报错如下,gcc版本太低 ^ server.c:5346:31: 错误:‘struct redisServer’没有名为‘server_cpulist’的成员 redisSetCpuAffinity(server.server_cpulist); ^ server.c: 在函数‘hasActiveC
解决方案1 1、改项目中.idea/workspace.xml配置文件,增加dynamic.classpath参数 2、搜索PropertiesComponent,添加如下 &lt;property name=&quot;dynamic.classpath&quot; value=&quot;tru
删除根组件app.vue中的默认代码后报错:Module Error (from ./node_modules/eslint-loader/index.js): 解决方案:关闭ESlint代码检测,在项目根目录创建vue.config.js,在文件中添加 module.exports = { lin
查看spark默认的python版本 [root@master day27]# pyspark /home/software/spark-2.3.4-bin-hadoop2.7/conf/spark-env.sh: line 2: /usr/local/hadoop/bin/hadoop: No s
使用本地python环境可以成功执行 import pandas as pd import matplotlib.pyplot as plt # 设置字体 plt.rcParams[&#39;font.sans-serif&#39;] = [&#39;SimHei&#39;] # 能正确显示负号 p
错误1:Request method ‘DELETE‘ not supported 错误还原:controller层有一个接口,访问该接口时报错:Request method ‘DELETE‘ not supported 错误原因:没有接收到前端传入的参数,修改为如下 参考 错误2:cannot r
错误1:启动docker镜像时报错:Error response from daemon: driver failed programming external connectivity on endpoint quirky_allen 解决方法:重启docker -&gt; systemctl r
错误1:private field ‘xxx‘ is never assigned 按Altʾnter快捷键,选择第2项 参考:https://blog.csdn.net/shi_hong_fei_hei/article/details/88814070 错误2:启动时报错,不能找到主启动类 #
报错如下,通过源不能下载,最后警告pip需升级版本 Requirement already satisfied: pip in c:\users\ychen\appdata\local\programs\python\python310\lib\site-packages (22.0.4) Coll
错误1:maven打包报错 错误还原:使用maven打包项目时报错如下 [ERROR] Failed to execute goal org.apache.maven.plugins:maven-resources-plugin:3.2.0:resources (default-resources)
错误1:服务调用时报错 服务消费者模块assess通过openFeign调用服务提供者模块hires 如下为服务提供者模块hires的控制层接口 @RestController @RequestMapping(&quot;/hires&quot;) public class FeignControl
错误1:运行项目后报如下错误 解决方案 报错2:Failed to execute goal org.apache.maven.plugins:maven-compiler-plugin:3.8.1:compile (default-compile) on project sb 解决方案:在pom.
参考 错误原因 过滤器或拦截器在生效时,redisTemplate还没有注入 解决方案:在注入容器时就生效 @Component //项目运行时就注入Spring容器 public class RedisBean { @Resource private RedisTemplate&lt;String
使用vite构建项目报错 C:\Users\ychen\work&gt;npm init @vitejs/app @vitejs/create-app is deprecated, use npm init vite instead C:\Users\ychen\AppData\Local\npm-