在INSERT … SELECT之后获取插入的ID

如果我从Oracle客户端(SQL Developer)运行它,则此SQL语句有效：

insert into Person (Name) select 'Bob' from dual

如果我通过Spring JDBC发布它,而不使用KeyHolder,它也可以工作：

final PreparedStatementCreator psc = new PreparedStatementCreator() {

    @Override
    public PreparedStatement createPreparedStatement(Connection con)
        throws SQLException
    {
        return con.prepareStatement(
                "insert into Person (Name) select 'Bob' from dual");
    }
};
jdbcOperations.update(psc);

但是我需要使用KeyHolder来获取新插入的行的ID.如果我改变上面的代码使用KeyHolder如下：

final KeyHolder keyHolder = new GeneratedKeyHolder();
final PreparedStatementCreator psc = new PreparedStatementCreator() {

    @Override
    public PreparedStatement createPreparedStatement(Connection con)
        throws SQLException
    {
        return con.prepareStatement(
            "insert into Person (Name) select 'Bob' from dual",new String[] {"PersonID"});
    }
};
jdbcOperations.update(psc,keyHolder);

…然后我收到此错误：

Exception in thread "main" org.springframework.jdbc.BadSqlGrammarException: PreparedStatementCallback; bad SQL grammar []; nested exception is java.sql.SQLSyntaxErrorException: ORA-00933: SQL command not properly ended
    at org.springframework.jdbc.support.SQLExceptionSubclassTranslator.doTranslate(SQLExceptionSubclassTranslator.java:94)
    at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:72)
    at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:80)
    at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java:602)
    at org.springframework.jdbc.core.JdbcTemplate.update(JdbcTemplate.java:842)
    at au.com.bisinfo.codecombo.logic.ImportServiceImpl.insertLoginRedirectRule(ImportServiceImpl.java:107)
    at au.com.bisinfo.codecombo.logic.ImportServiceImpl.runImport(ImportServiceImpl.java:68)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
    at java.lang.reflect.Method.invoke(Method.java:597)
    at org.springframework.aop.support.AopUtils.invokeJoinpointUsingReflection(AopUtils.java:309)
    at org.springframework.aop.framework.ReflectiveMethodInvocation.invokeJoinpoint(ReflectiveMethodInvocation.java:183)
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:150)
    at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:110)
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:172)
    at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:202)
    at $Proxy8.runImport(Unknown Source)
    at au.com.bisinfo.codecombo.ui.Main.main(Main.java:39)
Caused by: java.sql.SQLSyntaxErrorException: ORA-00933: SQL command not properly ended
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:439)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:395)
    at oracle.jdbc.driver.T4C8Oall.processError(T4C8Oall.java:802)
    at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:436)
    at oracle.jdbc.driver.T4CTTIfun.doRPC(T4CTTIfun.java:186)
    at oracle.jdbc.driver.T4C8Oall.doOALL(T4C8Oall.java:521)
    at oracle.jdbc.driver.T4CPreparedStatement.doOall8(T4CPreparedStatement.java:205)
    at oracle.jdbc.driver.T4CPreparedStatement.executeForRows(T4CPreparedStatement.java:1008)
    at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1307)
    at oracle.jdbc.driver.OraclePreparedStatement.executeInternal(OraclePreparedStatement.java:3449)
    at oracle.jdbc.driver.OraclePreparedStatement.executeUpdate(OraclePreparedStatement.java:3530)
    at oracle.jdbc.driver.OraclePreparedStatementWrapper.executeUpdate(OraclePreparedStatementWrapper.java:1350)
    at org.apache.commons.dbcp.DelegatingPreparedStatement.executeUpdate(DelegatingPreparedStatement.java:105)
    at org.apache.commons.dbcp.DelegatingPreparedStatement.executeUpdate(DelegatingPreparedStatement.java:105)
    at org.springframework.jdbc.core.JdbcTemplate$3.doInPreparedStatement(JdbcTemplate.java:844)
    at org.springframework.jdbc.core.JdbcTemplate$3.doInPreparedStatement(JdbcTemplate.java:1)
    at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java:586)
    ... 15 more

FWIW,一切都很好,如果我做一个INSERT … VALUES而不是INSERT … SELECT(虽然这对我没有帮助,因为我需要选择东西)：

final KeyHolder keyHolder = new GeneratedKeyHolder();
final PreparedStatementCreator psc = new PreparedStatementCreator() {

    @Override
    public PreparedStatement createPreparedStatement(Connection con)
        throws SQLException
    {
        return con.prepareStatement(
            "insert into Person (Name) values ('Bob')",keyHolder);

我正在使用：

> Spring JDBC 3.0.3.RELEASE
> JDBC驱动程序：ojdbc6.jar版本11.2.0.1.0
> RDBMS：Oracle9i版本9.2.0.5.0 – 生产
> commons-dbcp 1.4

注：我的应用程序需要使用标准SQL才能保持数据库中立,这排除了任何特定于Oracle的SQL(我不会在现实生活中选择“双重”).

谢谢你的帮助.

最佳答案

java.sql.Connection.prepareStatement(java.lang.String,int)界面清晰

Creates a default PreparedStatement object that has the capability to retrieve auto-generated keys

所以你使用的是错误的方法.尝试

return con.prepareStatement(
        "insert into Person (Name) select 'Bob' from dual",Statement.RETURN_GENERATED_KEYS);

代替