我正在尝试使用Rails 4.2的deliver_later方法设置联系表单.但是,我只能让deliver_now工作,因为deliver_later正在尝试序列化我的对象,每次都失败.
这是我的设置:
messages_controller.rb
class MessagesController < ApplicationController def new @message = Message.new end def create @message = Message.new(params[:message]) if @message.valid? ContactMailer.contact_form(@message).deliver_later redirect_to root_path,notice: "Message sent! Thank you for contacting us." else render :new end end end
contact_mailer.rb
class ContactMailer < ApplicationMailer default :to => Rails.application.secrets['email'] def contact_form(msg) @message = msg mail(:subject => msg.subject,from: msg.email) end end
message.rb
class Message include ActiveModel::Model include ActiveModel::Conversion ## Not sure if this is needed ## include ActiveModel::Serialization extend ActiveModel::Naming attr_accessor :name,:subject,:email,:body validates_presence_of :email,:body validates_format_of :email,with: /\A([^\s]+)((?:[-a-z0-9]\.)[a-z]{2,})\z/i validates_length_of :body,:maximum => 1000 def initialize(attributes = {}) attributes.each { |name,value| send("#{name}=",value) } end ## Not sure if this is needed ## def attribtues {'name' => nil,'subject' => nil,'email' => nil,'body' => nil} end end
调用ContactMailer.contact_form(@message).deliver_later时出现的错误是:
ActiveJob::SerializationError in MessagesController#create Unsupported argument type: Message Extracted source (around line #10): if @message.valid? ContactMailer.contact_form(@message).deliver_later redirect_to root_path,notice: "Message sent! Thank you for contacting us." else render :new
理想情况下,我希望这是一个后台进程.我会尽快添加像Sidekiq这样的东西,但我认为这是最好的事先修复这个序列化问题.
任何帮助是赞赏!谢谢 :)
解决方法
为了使用ActiveJob(这是delivery_later委托给你的)类,它需要能够通过其ID来唯一地标识该对象.此外,需要在反序列化时通过ID找到它(邮件/作业中不需要手动反序列化).
class Message ... include GlobalID::Identification ... def id ... end def self.find(id) ... end end
ActiveRecord将为您提供这些方法,但由于您没有使用它,您需要自己实现.决定您要存储记录的位置由您决定,但老实说,我认为通过使用ActiveRecord和下表可以更好地使用.
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