比较容易记忆的是用内置的set
l1 = ['b','c','d','b','a','a']
l2 = list(set(l1))
print l2
l2 = list(set(l1))
print l2
还有一种据说速度更快的,没测试过两者的速度差别
l1 = ['b','a']
l2 = {}.fromkeys(l1).keys()
print l2
l2 = {}.fromkeys(l1).keys()
print l2
这两种都有个缺点,祛除重复元素后排序变了:
['a','c','b','d']
如果想要保持他们原来的排序:
用list类的sort方法
l1 = ['b','a']
l2 = list(set(l1))
l2.sort(key=l1.index)
print l2
l2 = list(set(l1))
l2.sort(key=l1.index)
print l2
也可以这样写
l1 = ['b','a']
l2 = sorted(set(l1),key=l1.index)
print l2
l2 = sorted(set(l1),key=l1.index)
print l2
也可以用遍历
l1 = ['b','a']
l2 = []
for i in l1:
if not i in l2:
l2.append(i)
print l2
l2 = []
for i in l1:
if not i in l2:
l2.append(i)
print l2
上面的代码也可以这样写
l1 = ['b','a']
l2 = []
[l2.append(i) for i in l1 if not i in l2]
print l2
l2 = []
[l2.append(i) for i in l1 if not i in l2]
print l2
这样就可以保证排序不变了:
['b','d','a']
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