我在SQL查询中获取一些基本发票信息,并在同一查询中计算订单总额和付款总额.这是我到目前为止:
SELECT orders.billerID,orders.invoiceDate,orders.txnID,orders.bName,orders.bStreet1,orders.bStreet2,orders.bCity,orders.bState,orders.bZip,orders.bCountry,orders.sName,orders.sStreet1,orders.sStreet2,orders.sCity,orders.sState,orders.sZip,orders.sCountry,orders.paymentType,orders.invoiceNotes,orders.pFee,orders.shipping,orders.tax,orders.reasonCode,orders.txnType,orders.customerID,customers.firstName AS firstName,customers.lastName AS lastName,customers.businessName AS businessName,orderStatus.statusName AS orderStatus,SUM((orderItems.itemPrice * orderItems.itemQuantity)) + orders.shipping + orders.tax AS orderTotal,SUM(payments.amount) AS totalPayments <-- this sum FROM orders LEFT JOIN customers ON orders.customerID = customers.id LEFT JOIN orderStatus ON orders.orderStatus = orderStatus.id LEFT JOIN payments ON payments.orderID = orders.id <-- this join LEFT JOIN orderItems ON orderItems.orderID = orders.id
除了totalPayments列之外,一切都来自查询.数据库中有一个付款,其值为(10.00).查询提供的值是20.00(正好是两倍).我的理论是,由于某种原因,查询是两次“汇总”付款金额列.任何人都可以为我阐明这一点吗?
谢谢您的帮助!
解决方法
如果您在没有分组依据的情况下运行查询,您会看到某些付款有多行.那是因为你也加入了订单商品.对于orderitem和payment的每个组合,结果集将包含一行.
一种解决方案是将总和更改为:
,<earlier columns>,( select SUM(payments.amount) from payments where payments.orderID = orders.id ) AS totalPayments,<later columns>
这将确保多个订单项的付款不会多次汇总.
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