是否有任何资源可以测试jQuery脚本/扩展/插件/版本兼容性问题？
解决方法
刚刚编写了一个小的jQuery插件来帮助解决版本兼容性问题…随意改进它.
(function($) {
/**
* Used for version test cases.
*
* @param {string} left A string containing the version that will become
* the left hand operand.
* @param {string} oper The comparison operator to test against. By
* default,the "==" operator will be used.
* @param {string} right A string containing the version that will
* become the right hand operand. By default,the current jQuery
* version will be used.
*
* @return {boolean} Returns the evaluation of the expression,either
* true or false.
*/
$.isVersion = function(left,oper,right) {
if (left) {
var pre = /pre/i,replace = /[^\d]+/g,oper = oper || "==",right = right || $().jquery,l = left.replace(replace,''),r = right.replace(replace,l_len = l.length,r_len = r.length,l_pre = pre.test(left),r_pre = pre.test(right);
l = (r_len > l_len ? parseInt(l) * ((r_len - l_len) * 10) : parseInt(l));
r = (l_len > r_len ? parseInt(r) * ((l_len - r_len) * 10) : parseInt(r));
switch(oper) {
case "==": {
return (true === (l == r && (l_pre == r_pre)));
}
case ">=": {
return (true === (l >= r && (!l_pre || l_pre == r_pre)));
}
case "<=": {
return (true === (l <= r && (!r_pre || r_pre == l_pre)));
}
case ">": {
return (true === (l > r || (l == r && r_pre)));
}
case "<": {
return (true === (l < r || (l == r && l_pre)));
}
}
}
return false;
}
})(jQuery);
可以像这样使用：
$.isVersion("1.4.2"); // returns true,if $().jquery == "1.4.2"
$.isVersion("1.3.2",">"); // returns true if $().jquery > "1.3.2"
$.isVersion("1.3",">","1.2.6"); // returns true
$.isVersion("1.3.2","<","1.3.1"); // returns false
$.isVersion("1.4.0",">=","1.3.2"); // returns true
$.isVersion("1.4.1","<=","1.4.1"); // returns true
还支持预发布(版本比预版本重,因此1.4.0pre <1.4.0)：
$.isVersion("1.4.2","1.4.2pre"); // returns false
版权声明：本文内容由互联网用户自发贡献，该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请发送邮件至 dio@foxmail.com 举报，一经查实，本站将立刻删除。