我有如下实体
类ProgressNote
@Entity
public class ProgressNote implements Serializable{
@Id
private NotesKey notesKey = new NotesKey();
private Set类NotesKey
@Embeddable
public class NotesKey implements Serializable{
private Byte noteNumber;
@Temporal(javax.persistence.TemporalType.DATE)
@Column(name="ddate")
private Date noteDate;
private Patient patient;
public Byte getNoteNumber() {
return noteNumber;
}
public void setNoteNumber(Byte noteNumber) {
this.noteNumber = noteNumber;
}
public Date getNoteDate() {
return noteDate;
}
public void setNoteDate(Date noteDate) {
this.noteDate = noteDate;
}
@ManyToOne(fetch=FetchType.LAZY)
@Access(AccessType.PROPERTY)
public Patient getPatient() {
return patient;
}
public void setPatient(Patient patient) {
this.patient = patient;
}
@Override
public int hashCode() {
........
}
@Override
public boolean equals(Object obj) {
........
}
}
类PatientObjective
@Entity
public class PatientObjective implements Serializable{
@Id
private PatientObjectiveKey patientObjectiveKey;
public PatientObjectiveKey getPatientObjectiveKey() {
return patientObjectiveKey;
}
public void setPatientObjectiveKey(PatientObjectiveKey patientObjectiveKey) {
this.patientObjectiveKey = patientObjectiveKey;
}
}
类PatientObjectiveKey
@Embeddable
public class PatientObjectiveKey implements Serializable{
private Objective objective;
private Byte noteNumber;
@Temporal(javax.persistence.TemporalType.DATE)
@Column(name="ddate")
private Date noteDate;
private Patient patient;
@ManyToOne(fetch=FetchType.LAZY)
@Access(AccessType.PROPERTY)
public Objective getObjective() {
return objective;
}
public void setObjective(Objective objective) {
this.objective = objective;
}
public Byte getNoteNumber() {
return noteNumber;
}
public void setNoteNumber(Byte noteNumber) {
this.noteNumber = noteNumber;
}
public Date getNoteDate() {
return noteDate;
}
public void setNoteDate(Date noteDate) {
this.noteDate = noteDate;
}
@ManyToOne(fetch=FetchType.LAZY)
@Access(AccessType.PROPERTY)
public Patient getPatient() {
return patient;
}
public void setPatient(Patient patient) {
this.patient = patient;
}
@Override
public int hashCode() {
.......
}
@Override
public boolean equals(Object obj) {
........
}
}
我使用这个命名查询后
@NamedQuery(name = “findAllProgressNoteWithObjective”,query = “from
ProgressNote p inner join fetch p.patientObjectives as o where
p.notesKey.patient.id = :patientId)”) using spring hibernate template findByNamedQueryAndNamedParam
在表I中有2个ProgressNotes,其中一个具有单个目标,另一个具有17个目标.我在Java中得到如下结果.
查询生成为
select progressno0_.ddate as ddate46_0_,progressno0_.noteNumber as noteNumber46_0_,progressno0_.patient_id as patient17_46_0_,patientobj1_.ddate as ddate36_1_,patientobj1_.noteNumber as noteNumber36_1_,patientobj1_.objective_id as objective5_36_1_,patientobj1_.patient_id as patient6_36_1_,progressno0_.assessment as assessment46_0_,progressno0_.bloodPressure1 as bloodPre4_46_0_,progressno0_.bloodPressure2 as bloodPre5_46_0_,progressno0_.creationDate as creation6_46_0_,progressno0_.height as height46_0_,progressno0_.lastUpdatedDate as lastUpda8_46_0_,progressno0_.plans as plans46_0_,progressno0_.status as status46_0_,progressno0_.subject as subject46_0_,progressno0_.temprature as temprature46_0_,progressno0_.tempratureUnit as temprat13_46_0_,progressno0_.lastid as lastid46_0_,progressno0_.waist as waist46_0_,progressno0_.weight as weight46_0_,progressno0_.weightUnit as weightUnit46_0_,patientobj1_.remark as remark36_1_,patientobj1_.value as value36_1_,patientobj1_.ddate as ddate46_0__,patientobj1_.noteNumber as noteNumber46_0__,patientobj1_.patient_id as patient6_46_0__,patientobj1_.ddate as ddate0__,patientobj1_.noteNumber as noteNumber0__,patientobj1_.objective_id as objective5_0__,patientobj1_.patient_id as patient6_0__ from pnheader progressno0_ inner join pnobjremark patientobj1_ on progressno0_.ddate=patientobj1_.ddate and progressno0_.noteNumber=patientobj1_.noteNumber and progressno0_.patient_id=patientobj1_.patient_id where progressno0_.patient_id=?
题
问题我看到为什么我得到ProgressNote的多个单个实例(id = 152).有没有办法可以避免这种重复？
如果有人解释或指出我正确的方向,我将非常感激.
使用Hibernate 3.6,Mysql 5.6.10
最佳答案
使用不同：
select distinct p from ProgressNote p
inner join fetch p.patientObjectives as o
where p.notesKey.patient.id = :patientId)
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