如何解决将猫鼬findOneAndUpdate与GraphQL一起使用将返回null
我试图使用Mongoose和Graph QL运行一个基本的CRUD系统,但是当我使用findOneAndUpdate()函数GraphQL时抛出一个错误,告诉我我返回的是null,console.log已确认。
TypeDefs:
try:
query1 = "SELECT id FROM mdl_user WHERE username= ('%s')" % (self.searchuser2)
cursor.execute(query1)
linhas = cursor.fetchall()
for row in linhas:
self.userid = row[0]
# Pegando enrol_id do curso
query2 = "SELECT id FROM mdl_enrol WHERE courseid = %s AND enrol = 'manual'" % (self.rowidcourse)
cursor.execute(query2)
linhas = cursor.fetchall()
for row in linhas:
self.enrol_courseid = row[0]
# Inserindo o aluno e curso em mdl_user_enrolments
query3 = "INSERT INTO mdl_user_enrolments (status,enrolid,userid,timestart,timeend,timecreated,timemodified) VALUES(0,%s,1,1)" % (
self.enrol_courseid,self.userid)
cursor.execute(query3)
mariadb_connection.commit()
# Pegando contex_id do curso e aluno
query4 = "SELECT id FROM mdl_context WHERE instanceid=%s AND contextlevel=50" % (self.rowidcourse)
cursor.execute(query4)
linhas = cursor.fetchall()
for row in linhas:
self.contexid = row[0]
# Inserindo aluno no curso
query5 = "INSERT INTO mdl_role_assignments (roleid,contextid,timemodified) VALUES (5,2000)" \
% (self.contexid,self.userid)
cursor.execute(query5)
mariadb_connection.commit()
closedb()
tkinter.messagebox.showinfo("Muito bem!","Aluno cadastrado com sucesso.",parent=self.register1)
解析器:
type User {
id: ID!
username: String!
},type Mutation {
updateUser(
id: ID!
username: String!
):User
}
错误摘要:
async updateUser(_,args) {
const filter = {id: args.id}
const update = {$set:{username: args.username}}
return await User.findOneAndUpdate(filter,update,{new: true})
},
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