使用PowerShell找到并选择两个文件之间的xml属性

如何解决使用PowerShell找到并选择两个文件之间的xml属性

| 我有两个xml文件。 File1.xml：

<fileAsset fileAssetGuid=\"guid1\" assetTitle=\"Title1\" />
<fileAsset fileAssetGuid=\"guid2\" assetTitle=\"Title2\" />
<fileAsset fileAssetGuid=\"guid3\" assetTitle=\"Title3\" />

File2.xml：

<file id=\"guid1\" />
<file id=\"guid2\" />
<file id=\"guid3\" />

我知道File1.xml（\“ Title1 \”）中assetTitle的值。我需要使用该值来获取/选择file1.xml中的fileAssetGuid（\“ guid1 \”）值。然后，我需要使用file1.xml中fileAssetGuid的值（\“ guid1 \”）来找到file2.xml中的ID（\“ guid1 \”）。 如何在PowerShell中完成此操作？     

解决方法

        跟进斯特伊的建议。

Select-Xml -Path \"$pwd\\file1.xml\" -XPath \"/root/fileAsset[@assetTitle]\" | 
    ForEach {
        $id = $_.Node.fileAssetGuid
        Select-Xml -Path \"$pwd\\file2.xml\" -XPath \"/root/file[@id=\'$id\']\" | 
            ForEach { $_.Node }
    }

############
############

foreach( $assetGuideRecord in (Select-Xml -Path \"$pwd\\file1.xml\" -XPath \"/root/fileAsset[@assetTitle]\") ) {
    $id = $assetGuideRecord.node.fileAssetGuid

    foreach( $record in (Select-Xml -Path \"$pwd\\file2.xml\" -XPath \"/root/file[@id=\'$id\']\") ) {
        $record.node
    }
}

    ,        以下应该做您想做的（出于说明目的，我添加了一些内容）：

PS D:\\MiLu\\Dev\\PowerShell> cat .\\xmlsel1.xml
<file1>
<fileAsset fileAssetGuid=\"guid1\" assetTitle=\"Title1\" />
<fileAsset fileAssetGuid=\"guid2\" assetTitle=\"Title2\" />
<fileAsset fileAssetGuid=\"guid3\" assetTitle=\"Title3\" />
</file1>
PS D:\\MiLu\\Dev\\PowerShell> cat .\\xmlsel2.xml
<file2>
<file id=\"guid1\" data=\"one\" />
<file id=\"guid2\" data=\"two\" />
<file id=\"guid3\" data=\"three\" />
</file2>
PS D:\\MiLu\\Dev\\PowerShell> cat .\\xmlsel.ps1
$doc1 = [xml](get-content xmlsel1.xml)
$title = \"Title2\"
$asset = $doc1.file1.fileAsset | where { $_.assetTitle -eq $title }
# echo $asset
# echo $asset.assetTitle
# echo $asset.fileAssetGuid

$doc2 = [xml](get-content xmlsel2.xml)
$file = $doc2.file2.file | where { $_.id -eq $asset.fileAssetGuid }
# echo $file
echo $file.data
PS D:\\MiLu\\Dev\\PowerShell> .\\xmlsel.ps1
two

    ,        使用Xpath。

# Load up the XML 1. I\'ve used here-string,but anything goes.
[xml]$x1 = @\'
<root>
<fileAsset fileAssetGuid=\"guid1\" assetTitle=\"Title1\" />
<fileAsset fileAssetGuid=\"guid2\" assetTitle=\"Title2\" />
<fileAsset fileAssetGuid=\"guid3\" assetTitle=\"Title3\" />
</root>
\'@

# Ditto for XML 2.
[xml]$x2 = @\'
<root>
<file id=\"guid1\" />
<file id=\"guid2\" />
<file id=\"guid3\" />
</root> 
\'@

# Look for fileAsset element that has assettitle attribute
# which has value Title1
$n=$x1.SelectSinglenode(\"/root/fileAsset[@assetTitle=\'Title1\']\")

# Look for file node from XML2 that has id attribute
# that has value we got from XML1 with assetTitle 
$x2.SelectSingleNode(\"/root/file[@id=`\"$($n.fileAssetGuid)`\"]\")

# Remove the node by calling its parent\'s RemoveChild()
$n2.ParentNode.RemoveChild($n2)

# View final XML on the console
$x2.Save([console]::out)